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A relay coil is connected to a 210 V, 50 Hz supply. If it has resistance of 30Ω and an inductance of 0.5 H, the apparent power is
  • a)
    30 VA
  • b)
    275.6 VA
  • c)
    157 VA
  • d)
    187 VA
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A relay coil is connected to a 210 V, 50 Hz supply. If it has resistan...
Z= 30 + j(0.5)(2π)(50) = 30 + j157,
Apparent power  = 275.6 VA 
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Most Upvoted Answer
A relay coil is connected to a 210 V, 50 Hz supply. If it has resistan...
To calculate the current passing through the relay coil, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R).

Given:
Voltage (V) = 210 V
Frequency (f) = 50 Hz
Resistance (R) = 30 Ω

The formula for calculating the current (I) is:
I = V / R

Substituting the given values:
I = 210 V / 30 Ω
I ≈ 7 A

Therefore, the current passing through the relay coil is approximately 7 Amperes.
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A relay coil is connected to a 210 V, 50 Hz supply. If it has resistance of 30Ω and an inductance of 0.5 H, the apparent power isa)30 VAb)275.6 VAc)157 VAd)187 VACorrect answer is option 'B'. Can you explain this answer?
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