Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > A battery has a short-circuit current of 30 A...
Start Learning for Free
A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W?
Most Upvoted Answer
A battery has a short-circuit current of 30 A and an open circuit volt...
Calculating Power Dissipated by the Bulb:
1. Given Data:
- Short-circuit current (Isc) = 30 A
- Open circuit voltage (Voc) = 24 V
- Resistance of the bulb (R) = 2 ohms
2. Calculating Voltage Across the Bulb:
- When the bulb is connected to the battery, the circuit current flowing through the bulb will be equal to the short-circuit current of the battery, i.e., 30 A.
- Using Ohm's Law, we can calculate the voltage across the bulb:
V = I * R
V = 30 A * 2 ohms
V = 60 V
3. Calculating Power Dissipated by the Bulb:
- Power (P) can be calculated using the formula: P = V^2 / R
P = (60 V)^2 / 2 ohms
P = 3600 V^2 / 2 ohms
P = 1800 W
Therefore, the power dissipated by the bulb when connected to the battery is 1800 W.
1. Given Data:
- Short-circuit current (Isc) = 30 A
- Open circuit voltage (Voc) = 24 V
- Resistance of the bulb (R) = 2 ohms
2. Calculating Voltage Across the Bulb:
- When the bulb is connected to the battery, the circuit current flowing through the bulb will be equal to the short-circuit current of the battery, i.e., 30 A.
- Using Ohm's Law, we can calculate the voltage across the bulb:
V = I * R
V = 30 A * 2 ohms
V = 60 V
3. Calculating Power Dissipated by the Bulb:
- Power (P) can be calculated using the formula: P = V^2 / R
P = (60 V)^2 / 2 ohms
P = 3600 V^2 / 2 ohms
P = 1800 W
Therefore, the power dissipated by the bulb when connected to the battery is 1800 W.
Community Answer
A battery has a short-circuit current of 30 A and an open circuit volt...
1800 Watts
Attention Electronics and Communication Engineering (ECE) Students!
To make sure you are not studying endlessly, EduRev has designed Electronics and Communication Engineering (ECE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electronics and Communication Engineering (ECE).
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Similar Electronics and Communication Engineering (ECE) Doubts
Top Courses for Electronics and Communication Engineering (ECE)View all
A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W?
Question Description
A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W?.
A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W?.
Solutions for A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W? defined & explained in the simplest way possible. Besides giving the explanation of
A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W?, a detailed solution for A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W? has been provided alongside types of A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W? theory, EduRev gives you an
ample number of questions to practice A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is a)80 W b)1800 W c)112.5 W d)228 W? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
|
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
x
![]()
For Your Perfect Score in Electronics and Communication Engineering (ECE)
The Best you need at One Place
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup