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A single – phase, 50 Hz transformer has 40 primary turns and 520 secondary turns. The cross- sectional area of the core is 270 cm2. When the primary winding is connected to a 300 volts supply, determine (i) the maximum value of flux density in the core, and (ii) the voltage induced in the secondary winding.?
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A single – phase, 50 Hz transformer has 40 primary turns and 520 secon...
Given data:
- Frequency (f) = 50 Hz
- Number of primary turns (N1) = 40
- Number of secondary turns (N2) = 520
- Cross-sectional area of the core (A) = 270 cm²
- Supply voltage (V1) = 300 V

(i) Maximum value of flux density in the core:

The maximum value of flux density (Bm) in the core can be calculated using the formula:

Bm = (4 * V1 * 10^8) / (f * N1 * A)

Substituting the given values:

Bm = (4 * 300 * 10^8) / (50 * 40 * 270)

Simplifying the equation:

Bm = 0.4444 Tesla

Therefore, the maximum value of flux density in the core is 0.4444 Tesla.

(ii) Voltage induced in the secondary winding:

The voltage induced in the secondary winding (V2) can be calculated using the formula:

V2 = (N2 / N1) * V1

Substituting the given values:

V2 = (520 / 40) * 300

Simplifying the equation:

V2 = 3900 V

Therefore, the voltage induced in the secondary winding is 3900 V.

Explanation:

- The flux density (B) in a transformer core is directly proportional to the supply voltage (V1), number of turns (N1) in the primary winding, and the cross-sectional area of the core (A). It is inversely proportional to the frequency (f) of the supply.
- The maximum value of flux density (Bm) occurs when the supply voltage is at its peak value.
- The voltage induced in the secondary winding (V2) is directly proportional to the number of turns (N2) in the secondary winding and the supply voltage (V1).
- According to Faraday's law of electromagnetic induction, the voltage induced in the secondary winding is equal to the rate of change of magnetic flux linking with the winding.
- In this given scenario, the primary winding is connected to a 300 volts supply, and the secondary winding has more turns (520 turns) than the primary winding (40 turns). Hence, the voltage induced in the secondary winding is higher (3900 V) compared to the supply voltage.
- These calculations are based on the ideal transformer assumptions, neglecting losses and other non-ideal factors.
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A single – phase, 50 Hz transformer has 40 primary turns and 520 secondary turns. The cross- sectional area of the core is 270 cm2. When the primary winding is connected to a 300 volts supply, determine (i) the maximum value of flux density in the core, and (ii) the voltage induced in the secondary winding.?
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A single – phase, 50 Hz transformer has 40 primary turns and 520 secondary turns. The cross- sectional area of the core is 270 cm2. When the primary winding is connected to a 300 volts supply, determine (i) the maximum value of flux density in the core, and (ii) the voltage induced in the secondary winding.? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A single – phase, 50 Hz transformer has 40 primary turns and 520 secondary turns. The cross- sectional area of the core is 270 cm2. When the primary winding is connected to a 300 volts supply, determine (i) the maximum value of flux density in the core, and (ii) the voltage induced in the secondary winding.? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single – phase, 50 Hz transformer has 40 primary turns and 520 secondary turns. The cross- sectional area of the core is 270 cm2. When the primary winding is connected to a 300 volts supply, determine (i) the maximum value of flux density in the core, and (ii) the voltage induced in the secondary winding.?.
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