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A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calculate: (a) number of turns on primary winding; (b) secondary current (c) the cross-sectional area of the core, if the maximum flux density is 1.2 Tesla.?
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A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calcu...
Solution:
(a) Number of turns on primary winding:
We can use the formula,
Vp/Vs = Np/Ns
Where Vp and Vs are the primary and secondary voltages respectively, and Np and Ns are the number of turns on the primary and secondary windings respectively.
Substituting the given values, we get
3200/400 = Np/111
Np = 888
Therefore, the number of turns on the primary winding is 888.
(b) Secondary current:
We can use the formula,
Is = kVA/Vs
Where Is is the secondary current, kVA is the apparent power in kilovolts-amps, and Vs is the secondary voltage.
Substituting the given values, we get
Is = 80/400 = 0.2 kA
Therefore, the secondary current is 0.2 kA.
(c) Cross-sectional area of the core:
We can use the formula,
Bmax = (4π/10^4) × (kVA/Np)
Where Bmax is the maximum flux density in Tesla, kVA is the apparent power in kilovolts-amps, and Np is the number of turns on the primary winding.
Substituting the given values, we get
1.2 = (4π/10^4) × (80/888)
Solving for the cross-sectional area of the core, we get
A = (Bmax × 10^4)/ (4π × f × μ)
Where A is the cross-sectional area of the core in square meters, f is the frequency in hertz, and μ is the permeability of the core material.
Assuming a frequency of 50 Hz and a permeability of 4π × 10^-7 H/m, we get
A = (1.2 × 10^4)/ (4π × 50 × 4π × 10^-7) = 0.76 m^2
Therefore, the cross-sectional area of the core is 0.76 square meters.
(a) Number of turns on primary winding:
We can use the formula,
Vp/Vs = Np/Ns
Where Vp and Vs are the primary and secondary voltages respectively, and Np and Ns are the number of turns on the primary and secondary windings respectively.
Substituting the given values, we get
3200/400 = Np/111
Np = 888
Therefore, the number of turns on the primary winding is 888.
(b) Secondary current:
We can use the formula,
Is = kVA/Vs
Where Is is the secondary current, kVA is the apparent power in kilovolts-amps, and Vs is the secondary voltage.
Substituting the given values, we get
Is = 80/400 = 0.2 kA
Therefore, the secondary current is 0.2 kA.
(c) Cross-sectional area of the core:
We can use the formula,
Bmax = (4π/10^4) × (kVA/Np)
Where Bmax is the maximum flux density in Tesla, kVA is the apparent power in kilovolts-amps, and Np is the number of turns on the primary winding.
Substituting the given values, we get
1.2 = (4π/10^4) × (80/888)
Solving for the cross-sectional area of the core, we get
A = (Bmax × 10^4)/ (4π × f × μ)
Where A is the cross-sectional area of the core in square meters, f is the frequency in hertz, and μ is the permeability of the core material.
Assuming a frequency of 50 Hz and a permeability of 4π × 10^-7 H/m, we get
A = (1.2 × 10^4)/ (4π × 50 × 4π × 10^-7) = 0.76 m^2
Therefore, the cross-sectional area of the core is 0.76 square meters.
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A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calcu...
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A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calculate: (a) number of turns on primary winding; (b) secondary current (c) the cross-sectional area of the core, if the maximum flux density is 1.2 Tesla.?
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A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calculate: (a) number of turns on primary winding; (b) secondary current (c) the cross-sectional area of the core, if the maximum flux density is 1.2 Tesla.? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calculate: (a) number of turns on primary winding; (b) secondary current (c) the cross-sectional area of the core, if the maximum flux density is 1.2 Tesla.? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calculate: (a) number of turns on primary winding; (b) secondary current (c) the cross-sectional area of the core, if the maximum flux density is 1.2 Tesla.?.
A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calculate: (a) number of turns on primary winding; (b) secondary current (c) the cross-sectional area of the core, if the maximum flux density is 1.2 Tesla.? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calculate: (a) number of turns on primary winding; (b) secondary current (c) the cross-sectional area of the core, if the maximum flux density is 1.2 Tesla.? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 80 kVA, 3200/400 volts transformer has 111 turns on secondary. Calculate: (a) number of turns on primary winding; (b) secondary current (c) the cross-sectional area of the core, if the maximum flux density is 1.2 Tesla.?.
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