The electric field intensity is the negative gradient of the electric ...
Answer: a
Explanation: V = -∫E.dl is the integral form. On differentiating both sides, we get E = -Grad (V). Thus the electric field intensity is the negative gradient of the electric potential.
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The electric field intensity is the negative gradient of the electric ...
Explanation:
Definition of Electric Field Intensity and Electric Potential
- The electric field intensity (E) is a vector quantity that represents the force per unit charge experienced by a test charge at a given point in space.
- The electric potential (V) is a scalar quantity that represents the electric potential energy per unit charge of a test charge at a given point in space.
Relationship between Electric Field Intensity and Electric Potential
- The electric field intensity is the negative gradient of the electric potential. This means that:
E = -∇V
- Here, ∇ is the gradient operator, which represents the rate of change of a function with respect to its spatial coordinates.
- The negative sign indicates that the electric field points in the direction of decreasing potential.
Proof of the Relationship
- The proof of this relationship can be done using the definition of the gradient and the electric potential.
- The gradient of the electric potential is given by:
∇V = (∂V/∂x)i + (∂V/∂y)j + (∂V/∂z)k
- Here, i, j, and k are the unit vectors along the x, y, and z axes, respectively.
- The electric field intensity is given by:
E = F/q
- Here, F is the force experienced by a test charge q in the electric field.
- Using the definition of electric potential energy, we can write:
F = -∇Vq
- Substituting this in the expression for the electric field intensity, we get:
E = -∇V
- This proves the relationship between the electric field intensity and the electric potential.
Conclusion
- Therefore, the statement "The electric field intensity is the negative gradient of the electric potential" is true.
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