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The normal component of the electric flux density is always discontinuous at the interface. State True/False.
- a)True
- b)False
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The normal component of the electric flux density is always discontinu...
Answer: a
Explanation: In a dielectric-dielectric boundary, if a free surface charge density exists at the interface, then the normal components of the electric flux density are discontinuous at the boundary, which means Dn1 = Dn2.
Explanation: In a dielectric-dielectric boundary, if a free surface charge density exists at the interface, then the normal components of the electric flux density are discontinuous at the boundary, which means Dn1 = Dn2.
Most Upvoted Answer
The normal component of the electric flux density is always discontinu...
Explanation:
When an electromagnetic wave passes through a boundary between two different media, the wave experiences a change in its velocity and direction, which leads to a change in the electric field at the boundary. This change in the electric field causes a discontinuity in the normal component of the electric flux density, which is given by:
D2n - D1n = ρf
Where, D1n and D2n are the normal components of the electric flux density in the two media, and ρf is the free charge density at the interface.
This equation implies that the normal component of the electric flux density is discontinuous at the interface, and hence the statement "The normal component of the electric flux density is always discontinuous at the interface" is true.
Therefore, option 'A' is the correct answer.
When an electromagnetic wave passes through a boundary between two different media, the wave experiences a change in its velocity and direction, which leads to a change in the electric field at the boundary. This change in the electric field causes a discontinuity in the normal component of the electric flux density, which is given by:
D2n - D1n = ρf
Where, D1n and D2n are the normal components of the electric flux density in the two media, and ρf is the free charge density at the interface.
This equation implies that the normal component of the electric flux density is discontinuous at the interface, and hence the statement "The normal component of the electric flux density is always discontinuous at the interface" is true.
Therefore, option 'A' is the correct answer.
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The normal component of the electric flux density is always discontinuous at the interface. State True/False.a)Trueb)FalseCorrect answer is option 'A'. Can you explain this answer?
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