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(A): The electric field around a positive charge is outward.
(R): Gauss law states that the differential of the normal component of the outward electric flux density over a closed surface yields the positive charge enclosed.
  • a)
    Both A and R are true and R is a correct explanation of A
  • b)
    Both A and R are true but R is not a correct explanation of A
  • c)
    A is true but R is false
  • d)
    A is false but R is true
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
(A): The electric field around a positive charge is outward.(R): Gauss...
(A) The statement "The electric field around a positive charge is outward" is true. This is a fundamental property of electric charges. Electric field lines emanate radially outward from a positive charge and radially inward toward a negative charge.
(R) The statement "Gauss's law states that the differential of the normal component of the outward electric flux density over a closed surface yields the positive charge enclosed" is not correct. Gauss's law relates the electric flux through a closed surface to the total charge enclosed by that surface. It is a fundamental principle in electrostatics and is given by the equation:
∮ E · dA = Q_enclosed / ε₀
where ∮ E · dA represents the electric flux through the closed surface, Q_enclosed is the total charge enclosed by that surface, and ε₀ is the vacuum permittivity (a constant).
The incorrect part in statement (R) is the use of "outward electric flux density," which is not a standard term or concept in Gauss's law.
So, the correct answer is C: A is true, but R is false.
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(A): The electric field around a positive charge is outward.(R): Gauss...
The correct answer is option C: A is true but R is false.

Explanation:
Electric field around a positive charge is outward:
- The electric field is a vector quantity that represents the force experienced by a positive test charge placed in the vicinity of a source charge.
- For a positive charge, the electric field lines radiate outward from the charge and spread into the surrounding space. This is because positive charges repel each other, so the electric field lines diverge away from each other.

Gauss's Law and the electric flux density:
- Gauss's Law is a fundamental principle in electrostatics that relates the electric flux passing through a closed surface to the charge enclosed by that surface.
- The electric flux density is a measure of the electric field passing through a given area. It is defined as the electric flux per unit area.
- According to Gauss's Law, the integral of the normal component of the electric flux density over a closed surface is equal to the total charge enclosed by that surface divided by the permittivity of the medium.
- In other words, the differential (or infinitesimal) of the normal component of the outward electric flux density over a closed surface is proportional to the charge enclosed by that surface.

Evaluation of the given statements:
(A) The electric field around a positive charge is outward: This statement is true. As mentioned earlier, the electric field lines radiate outward from a positive charge.
(R) Gauss's Law states that the differential of the normal component of the outward electric flux density over a closed surface yields the positive charge enclosed: This statement is false. Gauss's Law relates the integral of the electric flux density over a closed surface to the charge enclosed, not the differential of the flux density.

Therefore, option C is the correct answer: A is true but R is false.
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(A): The electric field around a positive charge is outward.(R): Gauss law states that the differential of the normal component of the outward electric flux density over a closed surface yields the positive charge enclosed.a)Both A and R are true and R is a correct explanation of Ab)Both A and R are true but R is not a correct explanation of Ac)A is true but R is falsed)A is false but R is trueCorrect answer is option 'C'. Can you explain this answer?
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