If 8thterm of an A.P. is 15, then sum of its 15 terms isa)15b)0c)225d)...
Solution:
Given, 8thterm of an A.P. is 15
Let a be the first term and d be the common difference
We know that, the nth term of an A.P. is given by an = a + (n-1)d
So, the 8thterm is given by a8 = a + 7d = 15
Now, we need to find the sum of 15 terms of the A.P.
Formula for the sum of n terms of an A.P. is given by Sn = (n/2)[2a + (n-1)d]
Substituting n = 15, we get
S15 = (15/2)[2a + 14d]
We need to find the value of S15
To find a and d, we use the fact that a8 = 15
a8 = a + 7d = 15
We can write this as a = 15 - 7d
Substituting this in the formula for S15, we get
S15 = (15/2)[2(15-7d) + 14d]
Simplifying this expression, we get
S15 = (15/2)(30 - d)
S15 = 225 - (15/2)d
Hence, the sum of 15 terms of the A.P. is 225 - (15/2)d
Since we do not know the value of d, we cannot find the exact value of S15
However, we can say that the sum of 15 terms of the A.P. is a constant value of 225, irrespective of the value of d
Therefore, the correct answer is option 'C', i.e., 225.
If 8thterm of an A.P. is 15, then sum of its 15 terms isa)15b)0c)225d)...
In an arithmetic progression,
8th term = 15
a+(n-1)d = 15
a+7d = 15
2a + 14d = 30
sum of first n terms = (n/2)(2a+(n-1)d)
sum of first 15 terms = (15/2)(2a+(15-1)d)
=(15/2) 30
= 225.