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The capacitor of Gaussian channel of band width 4KHz, with noise PSD 10-9 wHz. When the signal Energy is 0.1. J.
  • a)
    5.44 x 104bith/sec
  • b)
    4.32 x 106bith/sec
  • c)
    8.42 x 104 bits/sec
  • d)
    9.34 x 108 bits/sec
Correct answer is option 'A'. Can you explain this answer?
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The capacitor of Gaussian channel of band width 4KHz, with noise PSD 1...

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Calculation of Channel Capacity using Gaussian Channel Formula

Given parameters are:
- Bandwidth (B) = 4 kHz
- Noise PSD (N0) = 10^-9 W/Hz
- Signal Energy (E) = 0.1 J

Step 1: Calculation of Signal Power
- Signal Power (P) = E/T, where T is the time duration of the signal
- As we don't have the time duration of the signal, we can assume it to be 1 second for simplicity
- Therefore, P = 0.1 W

Step 2: Calculation of Signal-to-Noise Ratio (SNR)
- SNR = P/N0B
- Substituting the given values, SNR = 25

Step 3: Calculation of Channel Capacity
- Channel Capacity (C) = B * log2(1 + SNR)
- Substituting the calculated SNR value, C = 4 * log2(26) = 5.44 x 10^4 bps

Therefore, the correct answer is option 'A' - 5.44 x 10^4 bps.
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The capacitor of Gaussian channel of band width 4KHz, with noise PSD 10-9 wHz. When the signal Energy is 0.1. J.a)5.44 x 104bith/secb)4.32 x 106bith/secc)8.42 x 104 bits/secd)9.34 x 108bits/secCorrect answer is option 'A'. Can you explain this answer?
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