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The capacity of a Binary Symmetric Channel (BSC) with cross-over probability 0.5 is _____. (Answer up to the nearest integer)
    Correct answer is '0'. Can you explain this answer?
    Most Upvoted Answer
    The capacity of a Binary Symmetric Channel (BSC) with cross-over prob...
    Introduction:
    The Binary Symmetric Channel (BSC) is a communication channel model that is widely used to analyze the performance of digital communication systems. It is a simple and commonly used model for studying the effects of channel noise.

    Explanation:
    The capacity of a communication channel is the maximum rate at which information can be reliably transmitted over the channel. In the case of a Binary Symmetric Channel, the capacity can be calculated using the Shannon Capacity formula.

    The Shannon Capacity formula for a Binary Symmetric Channel is given by:
    C = 1 - H(p)

    where C is the channel capacity, and H(p) is the entropy of the cross-over probability, p.

    Entropy Calculation:
    The entropy of the cross-over probability, H(p), can be calculated using the formula:
    H(p) = -p * log2(p) - (1-p) * log2(1-p)

    In the case of a cross-over probability of 0.5 (p=0.5), the entropy can be calculated as follows:
    H(0.5) = -0.5 * log2(0.5) - (1-0.5) * log2(1-0.5)
    = -0.5 * (-1) - 0.5 * (-1)
    = 0.5 + 0.5
    = 1

    Channel Capacity Calculation:
    Using the Shannon Capacity formula, we can calculate the channel capacity for a Binary Symmetric Channel with a cross-over probability of 0.5:
    C = 1 - H(0.5)
    = 1 - 1
    = 0

    Conclusion:
    The capacity of a Binary Symmetric Channel with a cross-over probability of 0.5 is 0. This means that no reliable information can be transmitted over such a channel. The channel is completely noisy, and any transmitted information will be corrupted.
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    Community Answer
    The capacity of a Binary Symmetric Channel (BSC) with cross-over prob...
    Given the binary symmetric channel (BSC) with crossover probability 0.6. So, we have
    p = 0.6
    so, the entropy is given as
    H(p) = Σp log21/p
    = 0.5log21/0.5 + 0.5log21/0.5 = 0.5 + 0.5 =1
    Hence, the capacity of channel is
    1 - H(p) =1-1 = 0
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