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A cylindrical vessel filled with water is released
on an inclined surface of angleθas shown in figure. The friction coefficient of surface with vessel isμ(< tanθ.)Then the constant angle made by the surface of water with the incline will be :

a
)
tan
1
μ

b)θ + tan-1μ
c)cot-1μ
d)θ - tan-1μ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A cylindrical vessel filled with water is released... more on an incli...
Since frictional force = pulling force
    i.e. μmgcosθ = mgsinθ
          tanθ = μ
           θ = tan-1μ​
here θ is angle made by surface of water with incline
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Most Upvoted Answer
A cylindrical vessel filled with water is released... more on an incli...
Figure shows forces acting on a ‘particle’ on the surface, with respect to vessel.
 are pseudo forces
θ  is angle between normal to the inclined surface and the resultant force.
The same angle will be formed between the surface of water and the inclined surface.
(∴ free surface is ⊥ to the resultant force acting on it)
The correct answer is:  tan-1μ
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A cylindrical vessel filled with water is released... more on an incli...
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A cylindrical vessel filled with water is released... more on an inclined surface of angleθas shown in figure. The friction coefficient of surface with vessel isμ(< tanθ.)Then the constant angle made by the surface of water with the incline will be :a)tan−1μb)θ + tan-1μc)cot-1μd)θ - tan-1μCorrect answer is option 'A'. Can you explain this answer?
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