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A collimated beam of pions originate from an accelerator and propagates in vacuum along a long straight beam pipe. The intensity of this beam was measured in the laboratory after a distance of 60 m and found to have dropped to one fourth of its intensity at the point of origin. If the proper half - life of a pion is 1.6 x 10-8 sec, the speed of the pions in the beam, as measured in the laboratory , must be nc. The value of n is _____  
    Correct answer is '0.99'. Can you explain this answer?
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    A collimated beam of pions originate from an accelerator and propagate...
    we know that
    x  = VΔt




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    A collimated beam of pions originate from an accelerator and propagate...
    Given:
    - Distance traveled by the pions: 60 m
    - Intensity dropped to one fourth of its intensity at the point of origin
    - Proper half-life of a pion: 1.6 x 10^-8 sec

    To Find:
    - The value of 'n', which represents the speed of the pions in the beam as measured in the laboratory

    Explanation:
    The intensity of a beam of particles decreases exponentially with distance traveled, according to the decay law. The decay law is given by the equation:

    I = I₀ * e^(-λx)

    Where:
    - I is the intensity at a distance x
    - I₀ is the initial intensity (at x = 0)
    - λ is the decay constant

    In this case, the intensity has dropped to one fourth of its intensity at the point of origin after traveling a distance of 60 m. Using this information, we can write the equation:

    (1/4) * I₀ = I₀ * e^(-λ * 60)

    Simplifying the equation, we get:

    e^(-λ * 60) = 1/4

    Taking the natural logarithm (ln) of both sides, we have:

    -λ * 60 = ln(1/4)

    Solving for λ, we get:

    λ = -ln(1/4) / 60

    The proper half-life (t₀.₅) of a particle is related to the decay constant (λ) by the equation:

    t₀.₅ = ln(2) / λ

    Substituting the value of λ, we can solve for t₀.₅:

    t₀.₅ = ln(2) / (-ln(1/4) / 60)

    Simplifying the equation, we get:

    t₀.₅ = 60 * ln(2) / ln(4)

    The speed of a particle can be related to its half-life using the equation:

    v = d / t₀.₅

    Where:
    - v is the speed of the particle
    - d is the distance traveled
    - t₀.₅ is the half-life of the particle

    Substituting the values, we have:

    v = 60 / (60 * ln(2) / ln(4))

    Simplifying the equation, we get:

    v = ln(4) / ln(2)

    Calculating the value, we find:

    v ≈ 1.386

    Hence, the value of 'n' is approximately 0.99 (as measured in the laboratory).
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    A collimated beam of pions originate from an accelerator and propagates in vacuum along a long straight beam pipe. The intensity of this beam was measured in the laboratory after a distance of 60 m and found to have dropped to one fourth of its intensity at the point of origin. If the proper half - life of a pion is 1.6 x 10-8sec, the speed of the pions in the beam, as measured in the laboratory , must be nc. The value of n is _____Correct answer is '0.99'. Can you explain this answer?
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