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A body moving along a straight line at 20m/s undergoes an acceleration of -4m/s2. After two seconds its speed will be
  • a)
    -8 m/s
  • b)
    12 m/s
  • c)
    16 m/s
  • d)
    24 m/s
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A body moving along a straight line at 20m/s undergoes an acceleration...
V = 20 m/s, a = 4 m/s^2, u = 0 m/s 
by using the formula 2as = v^2 - u^2 we get s = 50 m
then using the formula s = ut + 1/2at2 we get t = 5 s  then after two seconds is 5+2 = 7 s
now using formula v = u + at we get v( speed ) = 28 m/s
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Most Upvoted Answer
A body moving along a straight line at 20m/s undergoes an acceleration...
Given:
Initial velocity (u) = 20 m/s
Acceleration (a) = -4 m/s²
Time (t) = 2 s

To find:
Final velocity (v)

Formula:
v = u + at

Calculation:
Substituting the given values in the formula, we get:
v = u + at
v = 20 m/s + (-4 m/s²) x 2 s
v = 20 m/s - 8 m/s
v = 12 m/s

Therefore, the final velocity after 2 seconds will be 12 m/s.
Hence, option B is the correct answer.
Free Test
Community Answer
A body moving along a straight line at 20m/s undergoes an acceleration...
Given,
Initial velocity (u) = 20 m/s
Final velocity (v) = ?
Acceleration due to gravity (a) = - 4 
m/s^2

Time (t) = 2 sec
From First Equation of Motion:
v = u + at
v = 20 +(-) 4 * 2
v = 20 - 8
v = 12 m/s

Hence, the Correct Answer is Option B
You can cover in detail all the concepts of Speed, Velocity, and Acceleration by going through the doc:

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