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A 1 kHz sinusoidal signal is ideally sampled at 1400 samples/sec and the sampled signal is passed through an ideal low-pass filter with cut-off frequency 800 Hz. The output signal has the frequency kHz
Correct answer is '0.4'. Can you explain this answer?
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Verified Answer
A 1 kHz sinusoidal signal is ideally sampled at 1400 samples/sec and t...
Given that,
fm = 1 kHz
fs = 1.4 kHz
So, the output signal coli[..]iris two frequencies and they are
⇒(1.4 + 1) kHz and (1.4 - 1)I\Hz
⇒(2.4) kHz and (0.4) kHz
But, LPF has fc = 0.8 kHz
So, only 0.4 kHz will appear in output
But, LPF has fc = 0.8 kHz
So, only 0.4 kHz will appear in output
Most Upvoted Answer
A 1 kHz sinusoidal signal is ideally sampled at 1400 samples/sec and t...
Solution:
The sampling frequency is 1400 samples/sec. Therefore, the time period of the sampling signal is:
T = 1/f_s = 1/1400 = 0.000714 sec
The input signal is a 1 kHz sinusoidal signal. Therefore, the time period of the input signal is:
T_s = 1/f = 1/1000 = 0.001 sec
Since the input signal is sampled at a rate higher than the Nyquist rate (2f), the samples can be used to reconstruct the original signal.
The output signal is obtained by passing the sampled signal through an ideal low-pass filter with cutoff frequency 800 Hz.
The ideal low-pass filter removes all frequencies above 800 Hz and passes all frequencies below 800 Hz.
The output signal has a frequency equal to the highest frequency that can pass through the filter, which is 800 Hz.
Therefore, the output signal has a frequency of 0.8 kHz or 800 Hz.
Answer: 0.8 kHz or 800 Hz.
The sampling frequency is 1400 samples/sec. Therefore, the time period of the sampling signal is:
T = 1/f_s = 1/1400 = 0.000714 sec
The input signal is a 1 kHz sinusoidal signal. Therefore, the time period of the input signal is:
T_s = 1/f = 1/1000 = 0.001 sec
Since the input signal is sampled at a rate higher than the Nyquist rate (2f), the samples can be used to reconstruct the original signal.
The output signal is obtained by passing the sampled signal through an ideal low-pass filter with cutoff frequency 800 Hz.
The ideal low-pass filter removes all frequencies above 800 Hz and passes all frequencies below 800 Hz.
The output signal has a frequency equal to the highest frequency that can pass through the filter, which is 800 Hz.
Therefore, the output signal has a frequency of 0.8 kHz or 800 Hz.
Answer: 0.8 kHz or 800 Hz.
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A 1 kHz sinusoidal signal is ideally sampled at 1400 samples/sec and the sampled signal is passed through an ideal low-pass filter with cut-off frequency 800 Hz. The output signal has the frequency kHzCorrect answer is '0.4'. Can you explain this answer?
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