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For a particular intensity of incident light on a silicon pn junction solar cell, the photocurrent density (JL) is 2.5 mA/cm2 and the open-circuit voltage (Voc) is 0.451 V. consider thermal voltage (VT) to be 25mV. If the intensity of the incident light is increased by 20 times, assuming that the temperature remains unchanged. Voc (in volts) will be ______.
    Correct answer is '0.51 to 0.54'. Can you explain this answer?
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    For a particular intensity of incident light on a silicon pn junction ...

    Now if the intensity of the light is increased by 20 times it means their photocurrent will also increased by 20 times.
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    For a particular intensity of incident light on a silicon pn junction ...
    Given Information:
    - Photocurrent density (JL) = 2.5 mA/cm2
    - Open-circuit voltage (Voc) = 0.451 V
    - Thermal voltage (VT) = 25 mV
    - Intensity of incident light increased by 20 times

    Calculating Short-circuit Current (Jsc):
    The short-circuit current (Jsc) is the photocurrent density (JL) when the voltage across the solar cell is zero (short-circuited condition).

    Jsc = JL = 2.5 mA/cm2

    Calculating diode saturation current (Io):
    The diode saturation current (Io) can be calculated using the equation:

    Io = Jsc / (exp(Voc / VT) - 1)

    Substituting the given values:

    Io = 2.5 mA/cm2 / (exp(0.451 V / 25 mV) - 1)

    Calculating Voc for increased light intensity:
    When the intensity of incident light is increased by 20 times, the photocurrent density (JL) will also increase by the same factor.

    New JL = 20 * 2.5 mA/cm2 = 50 mA/cm2

    To find the new Voc, we use the equation:

    Voc = VT * ln(Jsc / JL + 1)

    Substituting the values:

    Voc = 25 mV * ln(2.5 mA/cm2 / 50 mA/cm2 + 1)

    Calculating the value using a calculator:

    Voc ≈ 0.54 V

    Conclusion:
    Therefore, the open-circuit voltage (Voc) for the increased light intensity is approximately 0.54 V, which falls within the given range of 0.51 V to 0.54 V.
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    For a particular intensity of incident light on a silicon pn junction solar cell, the photocurrent density (JL) is 2.5 mA/cm2 and the open-circuit voltage (Voc) is 0.451 V. consider thermal voltage (VT) to be 25mV. If the intensity of the incident light is increased by 20 times, assuming that the temperature remains unchanged. Voc (in volts) will be ______.Correct answer is '0.51 to 0.54'. Can you explain this answer?
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    For a particular intensity of incident light on a silicon pn junction solar cell, the photocurrent density (JL) is 2.5 mA/cm2 and the open-circuit voltage (Voc) is 0.451 V. consider thermal voltage (VT) to be 25mV. If the intensity of the incident light is increased by 20 times, assuming that the temperature remains unchanged. Voc (in volts) will be ______.Correct answer is '0.51 to 0.54'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about For a particular intensity of incident light on a silicon pn junction solar cell, the photocurrent density (JL) is 2.5 mA/cm2 and the open-circuit voltage (Voc) is 0.451 V. consider thermal voltage (VT) to be 25mV. If the intensity of the incident light is increased by 20 times, assuming that the temperature remains unchanged. Voc (in volts) will be ______.Correct answer is '0.51 to 0.54'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a particular intensity of incident light on a silicon pn junction solar cell, the photocurrent density (JL) is 2.5 mA/cm2 and the open-circuit voltage (Voc) is 0.451 V. consider thermal voltage (VT) to be 25mV. If the intensity of the incident light is increased by 20 times, assuming that the temperature remains unchanged. Voc (in volts) will be ______.Correct answer is '0.51 to 0.54'. Can you explain this answer?.
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