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A video transmission system transmits 625 picture frames per second each frame consist of 4002 pixel grid
with 64 intensity levels per pixel. The data rat e (in Gbps) of the system is
with 64 intensity levels per pixel. The data rat e (in Gbps) of the system is
__________________
Correct answer is between '6.2,6.5'. Can you explain this answer?
Verified Answer
A video transmission system transmits 625 picture frames per second ea...
Rate = 625 × 4002 × 64 = 6.4 Gbps
This question is part of UPSC exam. View all Electronics and Communication Engineering (ECE) courses
Most Upvoted Answer
A video transmission system transmits 625 picture frames per second ea...
To calculate the data rate of the video transmission system, we need to consider the number of bits transmitted per second. Here are the steps to calculate the data rate:
1. Calculate the total number of pixels in one frame:
- Each frame consists of a 4002 pixel grid, so the total number of pixels per frame is 4002.
2. Calculate the total number of intensity levels per pixel:
- Each pixel has 64 intensity levels.
3. Calculate the total number of bits per frame:
- Each pixel requires log2(64) = 6 bits to represent the intensity level.
- So, the total number of bits per frame is 4002 * 6 = 24,012 bits.
4. Calculate the total number of frames transmitted per second:
- The video transmission system transmits 625 frames per second.
5. Calculate the data rate:
- Multiply the number of frames per second by the number of bits per frame.
- Data rate (in bits per second) = 625 * 24,012 = 15,007,500 bits per second.
6. Convert the data rate to Gbps (Gigabits per second):
- 1 Gigabit = 1,000,000,000 bits.
- Divide the data rate (in bits per second) by 1,000,000,000 to get the data rate in Gbps.
- Data rate (in Gbps) = 15,007,500 / 1,000,000,000 ≈ 0.015 Gbps.
Therefore, the data rate of the video transmission system is approximately 0.015 Gbps.
Since the correct answer is between 6.2 and 6.5 Gbps, it seems that there might be a mistake in the given information or in the correct answer. It is unlikely for a video transmission system with a 4002 pixel grid and 64 intensity levels per pixel to have a data rate in the range of 6.2 to 6.5 Gbps.
1. Calculate the total number of pixels in one frame:
- Each frame consists of a 4002 pixel grid, so the total number of pixels per frame is 4002.
2. Calculate the total number of intensity levels per pixel:
- Each pixel has 64 intensity levels.
3. Calculate the total number of bits per frame:
- Each pixel requires log2(64) = 6 bits to represent the intensity level.
- So, the total number of bits per frame is 4002 * 6 = 24,012 bits.
4. Calculate the total number of frames transmitted per second:
- The video transmission system transmits 625 frames per second.
5. Calculate the data rate:
- Multiply the number of frames per second by the number of bits per frame.
- Data rate (in bits per second) = 625 * 24,012 = 15,007,500 bits per second.
6. Convert the data rate to Gbps (Gigabits per second):
- 1 Gigabit = 1,000,000,000 bits.
- Divide the data rate (in bits per second) by 1,000,000,000 to get the data rate in Gbps.
- Data rate (in Gbps) = 15,007,500 / 1,000,000,000 ≈ 0.015 Gbps.
Therefore, the data rate of the video transmission system is approximately 0.015 Gbps.
Since the correct answer is between 6.2 and 6.5 Gbps, it seems that there might be a mistake in the given information or in the correct answer. It is unlikely for a video transmission system with a 4002 pixel grid and 64 intensity levels per pixel to have a data rate in the range of 6.2 to 6.5 Gbps.
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A video transmission system transmits 625 picture frames per second each frame consist of 4002 pixel gridwith 64 intensity levels per pixel. The data rat e (in Gbps) of the system is__________________Correct answer is between '6.2,6.5'. Can you explain this answer?
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