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A paddle wheel used for stirring a liquid contained in a tank supplied 5000 kJ of work and during the stirring operation the tank lost 1500 kJ of heat to the surroundings. If the tank and liquid are considered as a system the change in its internal energy will be
  • a)
    1500 kJ
  • b)
    3500 kJ
  • c)
    5000 kJ
  • d)
    6500 kJ
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A paddle wheel used for stirring a liquid contained in a tank supplied...
From the first law of thermodynamics 
δQ = dU + δW
-1500 = dU - 5000
dU = 5000 - 1500 
dU = 3500 kJ
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Most Upvoted Answer
A paddle wheel used for stirring a liquid contained in a tank supplied...
Calculation of Change in Internal Energy of the System

Given:
Work done by the paddle wheel, W = 5000 kJ
Heat lost to the surroundings, Q = 1500 kJ

We know that the change in internal energy of a system is given by the first law of thermodynamics as:

ΔU = Q - W

Where,
ΔU = Change in internal energy of the system
Q = Heat supplied to the system
W = Work done by the system

Substituting the given values in the above equation, we get:

ΔU = 1500 kJ - 5000 kJ
ΔU = -3500 kJ

The negative sign indicates that the internal energy of the system has decreased. Therefore, the correct option is (b) 3500 kJ.
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