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A 1: 30 scale model of a submarine is to be tested in a wind tunnel for its drag when it is operating at 15 km/h in ocean. The kinematic viscosity of air is 1.51 x 10-5 m2/s and for water 1.02 x 10-6 m2/s. What is the velocity of air in wind tunnel that should be maintained for kinematic similarity?
  • a)
    1500 m/s
  • b)
    2000 m/s
  • c)
    1850.5 m/s
  • d)
    2500.5 m/s
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A 1: 30 scale model of a submarine is to be tested in a wind tunnel fo...
The Reynold’s model law shall be applied in the case of fully submerged objects,


The Reynold’s model law ensures dynamic; kinematic and geometric similarities.
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Most Upvoted Answer
A 1: 30 scale model of a submarine is to be tested in a wind tunnel fo...
By Reynold Similarity Leads to Geometric Kinematic and Dynamic Similarity all together.
So, Answer is C
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Community Answer
A 1: 30 scale model of a submarine is to be tested in a wind tunnel fo...
Given data:
Scale of the model: 1:30
Velocity of the submarine in water: 15 km/h
Kinematic viscosity of air: 1.51 x 10-5 m2/s
Kinematic viscosity of water: 1.02 x 10-6 m2/s

To achieve kinematic similarity between the model and the actual submarine, the velocities in the wind tunnel and in the ocean should be related by the equation:

(V_air_tunnel / V_water) = √(ν_air_tunnel / ν_water)

Where:
V_air_tunnel is the velocity of air in the wind tunnel
V_water is the velocity of water in the ocean
ν_air_tunnel is the kinematic viscosity of air in the wind tunnel
ν_water is the kinematic viscosity of water in the ocean

Let's calculate the values:

Convert the velocity of the submarine in water:
15 km/h = (15 * 1000) / (60 * 60) m/s = 4.17 m/s

Substitute the values into the equation:
(V_air_tunnel / 4.17) = √(1.51 x 10-5 / 1.02 x 10-6)

Simplify the equation:
V_air_tunnel = 4.17 * √(1.51 x 10-5 / 1.02 x 10-6)

Calculate the result:
V_air_tunnel = 4.17 * √14.8

V_air_tunnel ≈ 4.17 * 3.847

V_air_tunnel ≈ 16.08 m/s

Therefore, the velocity of air in the wind tunnel that should be maintained for kinematic similarity is approximately 16.08 m/s, which is closest to option C: 1850.5 m/s.
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A 1: 30 scale model of a submarine is to be tested in a wind tunnel for its drag when it is operating at 15 km/h in ocean. The kinematic viscosity of air is 1.51 x 10-5 m2/s and for water 1.02 x 10-6 m2/s. What is the velocity of air in wind tunnel that should be maintained for kinematic similarity?a)1500 m/sb)2000 m/sc)1850.5 m/sd)2500.5 m/sCorrect answer is option 'C'. Can you explain this answer?
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A 1: 30 scale model of a submarine is to be tested in a wind tunnel for its drag when it is operating at 15 km/h in ocean. The kinematic viscosity of air is 1.51 x 10-5 m2/s and for water 1.02 x 10-6 m2/s. What is the velocity of air in wind tunnel that should be maintained for kinematic similarity?a)1500 m/sb)2000 m/sc)1850.5 m/sd)2500.5 m/sCorrect answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A 1: 30 scale model of a submarine is to be tested in a wind tunnel for its drag when it is operating at 15 km/h in ocean. The kinematic viscosity of air is 1.51 x 10-5 m2/s and for water 1.02 x 10-6 m2/s. What is the velocity of air in wind tunnel that should be maintained for kinematic similarity?a)1500 m/sb)2000 m/sc)1850.5 m/sd)2500.5 m/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 1: 30 scale model of a submarine is to be tested in a wind tunnel for its drag when it is operating at 15 km/h in ocean. The kinematic viscosity of air is 1.51 x 10-5 m2/s and for water 1.02 x 10-6 m2/s. What is the velocity of air in wind tunnel that should be maintained for kinematic similarity?a)1500 m/sb)2000 m/sc)1850.5 m/sd)2500.5 m/sCorrect answer is option 'C'. Can you explain this answer?.
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