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The electric field strength at distant point, P, due to a point charge, +q, located at the origin, is 100 µ V/m. If the point charge is now enclosed by a perfectly conducting metal sheet sphere whose center is at the origin, then the electric field strength at the point, P, outside the sphere, becomes
- a)Zero
- b)– 100 µV/m
- c)100 µV/m
- d)50 µV/m
Correct answer is option 'A'. Can you explain this answer?
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The electric field strength at distant point, P, due to a point charge...
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The electric field strength at distant point, P, due to a point charge...
Explanation:
When a point charge q is located at the origin, the electric field strength at a distant point P is given by:
E = kq/r^2
where k is the Coulomb constant, q is the charge, and r is the distance between the point charge and the distant point P.
Given that the electric field strength at point P is 100 V/m, we can write:
100 = kq/r^2
Now, when the point charge q is enclosed by a perfectly conducting metal sheet sphere, the electric field lines originating from the point charge will terminate on the surface of the sphere. This is because the metal sheet is a conductor and any electric field inside it must be zero. Therefore, the electric field outside the sphere will be due to the induced charges on the surface of the sphere.
Since the sphere is perfectly conducting, the electric potential on its surface must be constant. This means that the electric field outside the sphere must be perpendicular to the surface and have the same magnitude everywhere. This is known as the electric field shielding effect.
Therefore, when we place a perfectly conducting metal sheet sphere around the point charge, the electric field at point P outside the sphere becomes zero. This is because the electric field lines originating from the point charge terminate on the surface of the sphere and do not reach point P.
Hence, the correct option is A) Zero.
When a point charge q is located at the origin, the electric field strength at a distant point P is given by:
E = kq/r^2
where k is the Coulomb constant, q is the charge, and r is the distance between the point charge and the distant point P.
Given that the electric field strength at point P is 100 V/m, we can write:
100 = kq/r^2
Now, when the point charge q is enclosed by a perfectly conducting metal sheet sphere, the electric field lines originating from the point charge will terminate on the surface of the sphere. This is because the metal sheet is a conductor and any electric field inside it must be zero. Therefore, the electric field outside the sphere will be due to the induced charges on the surface of the sphere.
Since the sphere is perfectly conducting, the electric potential on its surface must be constant. This means that the electric field outside the sphere must be perpendicular to the surface and have the same magnitude everywhere. This is known as the electric field shielding effect.
Therefore, when we place a perfectly conducting metal sheet sphere around the point charge, the electric field at point P outside the sphere becomes zero. This is because the electric field lines originating from the point charge terminate on the surface of the sphere and do not reach point P.
Hence, the correct option is A) Zero.
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The electric field strength at distant point, P, due to a point charge, +q, located at the origin, is 100 µ V/m. If the point charge is now enclosed by a perfectly conducting metal sheet sphere whose center is at the origin, then the electric field strength at the point, P, outside the sphere, becomesa)Zerob)– 100 µV/mc)100 µV/md)50 µV/mCorrect answer is option 'A'. Can you explain this answer?
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