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For a medium,conductivity sigma is equal to 58 x 10^6 siemen/m,E base r is equal to 1. find out the conduction and displacement current density if the magnitude of electric field intensity is given by E is equal to 150 in(10^10t) volt/m?
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For a medium,conductivity sigma is equal to 58 x 10^6 siemen/m,E base ...
Given:
Conduction Current Density:
The conduction current density can be calculated using the equation:
J = sigma * E
Where J is the current density, sigma is the conductivity, and E is the electric field intensity.
Substituting the given values, we get:
J = 58 x 10^6 * 150 in(10^10t)
J = 8.7 in(10^19t) A/m^2
Therefore, the conduction current density is 8.7 in(10^19t) A/m^2.
Displacement Current Density:
The displacement current density can be calculated using the equation:
Jd = Er * dE/dt
Where Jd is the displacement current density, Er is the permittivity of free space, and dE/dt is the rate of change of electric field intensity with time.
Substituting the given values, we get:
Jd = 1 * d/dt(150 in(10^10t))
Jd = 1.5 in(10^20t) A/m^2
Therefore, the displacement current density is 1.5 in(10^20t) A/m^2.
Explanation:
- Conductivity, sigma = 58 x 10^6 S/m
- Permittivity of free space, E base r = 1
- Electric field intensity, E = 150 in(10^10t) V/m
Conduction Current Density:
The conduction current density can be calculated using the equation:
J = sigma * E
Where J is the current density, sigma is the conductivity, and E is the electric field intensity.
Substituting the given values, we get:
J = 58 x 10^6 * 150 in(10^10t)
J = 8.7 in(10^19t) A/m^2
Therefore, the conduction current density is 8.7 in(10^19t) A/m^2.
Displacement Current Density:
The displacement current density can be calculated using the equation:
Jd = Er * dE/dt
Where Jd is the displacement current density, Er is the permittivity of free space, and dE/dt is the rate of change of electric field intensity with time.
Substituting the given values, we get:
Jd = 1 * d/dt(150 in(10^10t))
Jd = 1.5 in(10^20t) A/m^2
Therefore, the displacement current density is 1.5 in(10^20t) A/m^2.
Explanation:
- The given values of conductivity, permittivity of free space, and electric field intensity are used to calculate the conduction and displacement current densities.
- The conduction current density is calculated using the equation J = sigma * E, where sigma is the conductivity and E is the electric field intensity.
- The displacement current density is calculated using the equation Jd = Er * dE/dt, where Er is the permittivity of free space and dE/dt is the rate of change of electric field intensity with time.
- The values of conduction and displacement current densities are calculated and expressed in appropriate units.
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For a medium,conductivity sigma is equal to 58 x 10^6 siemen/m,E base r is equal to 1. find out the conduction and displacement current density if the magnitude of electric field intensity is given by E is equal to 150 in(10^10t) volt/m?
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For a medium,conductivity sigma is equal to 58 x 10^6 siemen/m,E base r is equal to 1. find out the conduction and displacement current density if the magnitude of electric field intensity is given by E is equal to 150 in(10^10t) volt/m? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about For a medium,conductivity sigma is equal to 58 x 10^6 siemen/m,E base r is equal to 1. find out the conduction and displacement current density if the magnitude of electric field intensity is given by E is equal to 150 in(10^10t) volt/m? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a medium,conductivity sigma is equal to 58 x 10^6 siemen/m,E base r is equal to 1. find out the conduction and displacement current density if the magnitude of electric field intensity is given by E is equal to 150 in(10^10t) volt/m?.
For a medium,conductivity sigma is equal to 58 x 10^6 siemen/m,E base r is equal to 1. find out the conduction and displacement current density if the magnitude of electric field intensity is given by E is equal to 150 in(10^10t) volt/m? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about For a medium,conductivity sigma is equal to 58 x 10^6 siemen/m,E base r is equal to 1. find out the conduction and displacement current density if the magnitude of electric field intensity is given by E is equal to 150 in(10^10t) volt/m? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a medium,conductivity sigma is equal to 58 x 10^6 siemen/m,E base r is equal to 1. find out the conduction and displacement current density if the magnitude of electric field intensity is given by E is equal to 150 in(10^10t) volt/m?.
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