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Consider the following organization of main memory and cache memory:
Main memory: 64K x 16
Cache memory; 256 x 16
Memory is word-addressable and block size is of 8 words. Determine the size of tag field if direct mapping is used for transforming data from main memory to cache memory.
Main memory: 64K x 16
Cache memory; 256 x 16
Memory is word-addressable and block size is of 8 words. Determine the size of tag field if direct mapping is used for transforming data from main memory to cache memory.
- a)5 bits
- b)6 bits
- c)7 bits
- d)8 bits
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Consider the following organization of main memory and cache memory:Ma...
Memory address: 16 bits
Number of words in cache = 256 = 28
Number of words in cache = 256 = 28
Most Upvoted Answer
Consider the following organization of main memory and cache memory:Ma...
Explanation:
To determine the size of the tag field, we need to consider the block size and the total number of blocks in the cache memory.
Block Size:
The block size is given as 8 words. Since memory is word-addressable, each word consists of 16 bits. Therefore, the block size can be calculated as:
Block Size = 8 words × 16 bits/word
Block Size = 128 bits
Total Number of Blocks:
The cache memory size is given as 256 x 16. Since memory is word-addressable, the total number of blocks can be calculated by dividing the cache memory size by the block size:
Total Number of Blocks = (256 x 16) bits ÷ 128 bits
Total Number of Blocks = 256
Direct Mapping:
In direct mapping, each block in the main memory is mapped to a specific block in the cache memory. The block number in the cache memory is determined by the block number in the main memory. The remaining bits in the main memory address are divided into tag bits and offset bits.
Calculating the Size of Tag Field:
To determine the size of the tag field, we need to find the number of bits required to represent the total number of blocks. Since the total number of blocks is 256, we need 8 bits to represent it.
Therefore, the size of the tag field is equal to the number of bits in the main memory address minus the number of bits used for the block number:
Size of Tag Field = Number of bits in main memory address - Number of bits used for block number
Size of Tag Field = 16 bits - 8 bits
Size of Tag Field = 8 bits
Hence, the correct answer is option 'D', 8 bits.
To determine the size of the tag field, we need to consider the block size and the total number of blocks in the cache memory.
Block Size:
The block size is given as 8 words. Since memory is word-addressable, each word consists of 16 bits. Therefore, the block size can be calculated as:
Block Size = 8 words × 16 bits/word
Block Size = 128 bits
Total Number of Blocks:
The cache memory size is given as 256 x 16. Since memory is word-addressable, the total number of blocks can be calculated by dividing the cache memory size by the block size:
Total Number of Blocks = (256 x 16) bits ÷ 128 bits
Total Number of Blocks = 256
Direct Mapping:
In direct mapping, each block in the main memory is mapped to a specific block in the cache memory. The block number in the cache memory is determined by the block number in the main memory. The remaining bits in the main memory address are divided into tag bits and offset bits.
Calculating the Size of Tag Field:
To determine the size of the tag field, we need to find the number of bits required to represent the total number of blocks. Since the total number of blocks is 256, we need 8 bits to represent it.
Therefore, the size of the tag field is equal to the number of bits in the main memory address minus the number of bits used for the block number:
Size of Tag Field = Number of bits in main memory address - Number of bits used for block number
Size of Tag Field = 16 bits - 8 bits
Size of Tag Field = 8 bits
Hence, the correct answer is option 'D', 8 bits.
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