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When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):
Correct answer is between '0.220,0.230'. Can you explain this answer?
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When 0.045 mole of NaOH was added to one litre of buffer solution, its...
Given:
- Amount of NaOH added = 0.045 mole
- Volume of buffer solution = 1 litre
- pH change = 5.92 - 5.72 = 0.2
To calculate buffer index:
Step 1: Calculate the concentration of the buffer solution
The concentration of the buffer solution can be calculated using the formula:
C = n/V
Where:
- C is the concentration of the buffer solution
- n is the number of moles of the solute (NaOH) added to the solution
- V is the volume of the solution
Plugging in the given values:
C = 0.045 mole / 1 litre = 0.045 M
Step 2: Calculate the buffer index
The buffer index can be calculated using the formula:
Buffer index = ΔpH / Δ(logC)
Where:
- ΔpH is the change in pH of the buffer solution
- Δ(logC) is the change in the logarithm of the concentration of the buffer solution
Plugging in the given values:
Buffer index = 0.2 / Δ(logC)
Step 3: Calculate the change in the logarithm of the concentration
The change in the logarithm of the concentration can be calculated using the formula:
Δ(logC) = log(C2) - log(C1)
Where:
- C1 is the initial concentration of the buffer solution
- C2 is the final concentration of the buffer solution
Plugging in the given values:
Δ(logC) = log(0.045 M) - log(C1)
Step 4: Calculate the buffer index
Plugging in the calculated values from Step 2 and Step 3:
Buffer index = 0.2 / (log(0.045 M) - log(C1))
Step 5: Solve for C1
To find the value of C1, we need to rearrange the equation and solve for C1:
Buffer index = 0.2 / (log(0.045 M) - log(C1))
(log(0.045 M) - log(C1)) = 0.2 / Buffer index
log(C1) = log(0.045 M) - 0.2 / Buffer index
C1 = 10^(log(0
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When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer?
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