Chemistry Exam > Chemistry Questions > When 0.045 mole of NaOH was added to one litr...
Start Learning for Free
When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):
Correct answer is between '0.220,0.230'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
When 0.045 mole of NaOH was added to one litre of buffer solution, its...
Free Test
FREE
| Start Free Test |
Community Answer
When 0.045 mole of NaOH was added to one litre of buffer solution, its...
Given:
- Amount of NaOH added = 0.045 mole
- Volume of buffer solution = 1 litre
- pH change = 5.92 - 5.72 = 0.2
To calculate buffer index:
Step 1: Calculate the concentration of the buffer solution
The concentration of the buffer solution can be calculated using the formula:
C = n/V
Where:
- C is the concentration of the buffer solution
- n is the number of moles of the solute (NaOH) added to the solution
- V is the volume of the solution
Plugging in the given values:
C = 0.045 mole / 1 litre = 0.045 M
Step 2: Calculate the buffer index
The buffer index can be calculated using the formula:
Buffer index = ΔpH / Δ(logC)
Where:
- ΔpH is the change in pH of the buffer solution
- Δ(logC) is the change in the logarithm of the concentration of the buffer solution
Plugging in the given values:
Buffer index = 0.2 / Δ(logC)
Step 3: Calculate the change in the logarithm of the concentration
The change in the logarithm of the concentration can be calculated using the formula:
Δ(logC) = log(C2) - log(C1)
Where:
- C1 is the initial concentration of the buffer solution
- C2 is the final concentration of the buffer solution
Plugging in the given values:
Δ(logC) = log(0.045 M) - log(C1)
Step 4: Calculate the buffer index
Plugging in the calculated values from Step 2 and Step 3:
Buffer index = 0.2 / (log(0.045 M) - log(C1))
Step 5: Solve for C1
To find the value of C1, we need to rearrange the equation and solve for C1:
Buffer index = 0.2 / (log(0.045 M) - log(C1))
(log(0.045 M) - log(C1)) = 0.2 / Buffer index
log(C1) = log(0.045 M) - 0.2 / Buffer index
C1 = 10^(log(0
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer?
Question Description
When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer?.
When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer?.
Solutions for When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer?, a detailed solution for When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer? has been provided alongside types of When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice When 0.045 mole of NaOH was added to one litre of buffer solution, its pH changes from 5.72 to 5.92. Calculate buffer index (rounded up to three decimal places):Correct answer is between '0.220,0.230'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup