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A 50 mA basic d'Arsonval movement with an internal resistance of 500W is to be used as a voltmeter. The value of the multiplier resistance required to measure a full scale voltage range of 0-5 volts is
- a)999.5KW
- b)99.5KW
- c)9.99KW
- d)0.99KW
Correct answer is option 'B'. Can you explain this answer?
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A 50 mA basic d'Arsonval movement with an internal resistance of 5...
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**Given Information:**
- Basic d'Arsonval movement with a current of 50 mA (0.05 A).
- Internal resistance of the movement is 500 Ω.
- Voltage range to be measured is 0-5 V.
**Explanation:**
The basic d'Arsonval movement is a type of moving coil instrument used for measuring current or voltage. In this case, it is being used as a voltmeter to measure the voltage range of 0-5 V.
The full-scale current for the voltmeter can be calculated using Ohm's Law:
\[I = \frac{V}{R}\]
Where:
- I is the current flowing through the voltmeter.
- V is the voltage to be measured.
- R is the total resistance of the voltmeter circuit.
In this case, the current flowing through the voltmeter is 50 mA (0.05 A) and the voltage to be measured is 5 V. Therefore, we can rearrange Ohm's Law to find the total resistance:
\[R = \frac{V}{I}\]
\[R = \frac{5}{0.05}\]
\[R = 100\]
The total resistance of the voltmeter circuit should be 100 Ω in order to measure a full-scale voltage range of 0-5 V.
Since the internal resistance of the movement is already given as 500 Ω, we need to add an external resistance (multiplier resistance) in series with the movement to achieve a total resistance of 100 Ω.
The value of the multiplier resistance can be calculated as:
\[R_{multiplier} = R_{total} - R_{internal}\]
\[R_{multiplier} = 100 - 500\]
\[R_{multiplier} = -400\]
However, resistance cannot be negative, so we take the absolute value of -400:
\[R_{multiplier} = 400\]
Therefore, the value of the multiplier resistance required to measure a full-scale voltage range of 0-5 V is 400 Ω.
Converting 400 Ω to kilohms:
\[400 \, \Omega = 0.4 \, \text{k}\Omega\]
So, the correct answer is option (b) 99.5 kΩ (approximately 0.4 kΩ).
- Basic d'Arsonval movement with a current of 50 mA (0.05 A).
- Internal resistance of the movement is 500 Ω.
- Voltage range to be measured is 0-5 V.
**Explanation:**
The basic d'Arsonval movement is a type of moving coil instrument used for measuring current or voltage. In this case, it is being used as a voltmeter to measure the voltage range of 0-5 V.
The full-scale current for the voltmeter can be calculated using Ohm's Law:
\[I = \frac{V}{R}\]
Where:
- I is the current flowing through the voltmeter.
- V is the voltage to be measured.
- R is the total resistance of the voltmeter circuit.
In this case, the current flowing through the voltmeter is 50 mA (0.05 A) and the voltage to be measured is 5 V. Therefore, we can rearrange Ohm's Law to find the total resistance:
\[R = \frac{V}{I}\]
\[R = \frac{5}{0.05}\]
\[R = 100\]
The total resistance of the voltmeter circuit should be 100 Ω in order to measure a full-scale voltage range of 0-5 V.
Since the internal resistance of the movement is already given as 500 Ω, we need to add an external resistance (multiplier resistance) in series with the movement to achieve a total resistance of 100 Ω.
The value of the multiplier resistance can be calculated as:
\[R_{multiplier} = R_{total} - R_{internal}\]
\[R_{multiplier} = 100 - 500\]
\[R_{multiplier} = -400\]
However, resistance cannot be negative, so we take the absolute value of -400:
\[R_{multiplier} = 400\]
Therefore, the value of the multiplier resistance required to measure a full-scale voltage range of 0-5 V is 400 Ω.
Converting 400 Ω to kilohms:
\[400 \, \Omega = 0.4 \, \text{k}\Omega\]
So, the correct answer is option (b) 99.5 kΩ (approximately 0.4 kΩ).
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A 50 mA basic d'Arsonval movement with an internal resistance of 500W is to be used as a voltmeter. The value of the multiplier resistance required to measure a full scale voltage range of 0-5 volts isa)999.5KWb)99.5KWc)9.99KWd)0.99KWCorrect answer is option 'B'. Can you explain this answer?
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A 50 mA basic d'Arsonval movement with an internal resistance of 500W is to be used as a voltmeter. The value of the multiplier resistance required to measure a full scale voltage range of 0-5 volts isa)999.5KWb)99.5KWc)9.99KWd)0.99KWCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50 mA basic d'Arsonval movement with an internal resistance of 500W is to be used as a voltmeter. The value of the multiplier resistance required to measure a full scale voltage range of 0-5 volts isa)999.5KWb)99.5KWc)9.99KWd)0.99KWCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 mA basic d'Arsonval movement with an internal resistance of 500W is to be used as a voltmeter. The value of the multiplier resistance required to measure a full scale voltage range of 0-5 volts isa)999.5KWb)99.5KWc)9.99KWd)0.99KWCorrect answer is option 'B'. Can you explain this answer?.
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