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In a 8085 system, a PUSH operation requires more clock cycles than a POP operation, which one
of the following options is the correct reason for this?
  • a)
    For POP, the data transceivers remain in the same direction as for instruction fetch (memory to processor), whereas for PUSH their direction has to be reversed
  • b)
    Memory write operations are slower than memory read operations in an 8085 bases system.
  • c)
    The stack pointer needs to be pre-determined before writing registers in a PUSH, whereas a
    POP operation uses the address already in the stack pointer.
  • d)
    Order of register has to be interchanged for a PUSH operation, whereas POP uses their natural order.
Correct answer is option 'C'. Can you explain this answer?
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In a 8085 system, a PUSH operation requires more clock cycles than a P...
Push takes 12T states due to pre decrement and pop takes 10T states.
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In a 8085 system, a PUSH operation requires more clock cycles than a P...

In an 8085 system, a PUSH operation requires more clock cycles than a POP operation due to the following reasons:

Stack Pointer Pre-Determination:
- When performing a PUSH operation, the stack pointer needs to be pre-determined before writing the data into the stack.
- The stack pointer is a 16-bit register that contains the address of the top of the stack.
- Before executing a PUSH instruction, the stack pointer needs to be decremented by 2 to make space for the data being pushed onto the stack.
- This pre-determination of the stack pointer requires additional clock cycles.

Data Direction Reversal:
- During a POP operation, the data transceivers remain in the same direction as for instruction fetch, which is memory to processor.
- However, during a PUSH operation, the data transceivers need to be reversed to transfer data from the processor to memory.
- Reversing the direction of the data transceivers involves additional circuitry and logic, resulting in more clock cycles being required for a PUSH operation.

Memory Write Operations:
- In an 8085 system, memory write operations are generally slower than memory read operations.
- During a PUSH operation, the data is written into the memory stack.
- This memory write operation takes more time compared to a memory read operation in a POP operation.
- Therefore, the additional time required for memory write operations contributes to the increased clock cycles for a PUSH operation.

Conclusion:
The correct reason for a PUSH operation requiring more clock cycles than a POP operation in an 8085 system is that the stack pointer needs to be pre-determined before writing registers in a PUSH operation, whereas a POP operation uses the address already in the stack pointer. Additionally, the data direction reversal and slower memory write operations during a PUSH operation also contribute to the increased clock cycles.
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In a 8085 system, a PUSH operation requires more clock cycles than a POP operation, which oneof the following options is the correct reason for this?a)For POP, the data transceivers remain in the same direction as for instruction fetch (memory to processor), whereas for PUSH their direction has to be reversedb)Memory write operations are slower than memory read operations in an 8085 bases system.c)The stack pointer needs to be pre-determined before writing registers in a PUSH, whereas aPOP operation uses the address already in the stack pointer.d)Order of register has to be interchanged for a PUSH operation, whereas POP uses their natural order.Correct answer is option 'C'. Can you explain this answer?
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In a 8085 system, a PUSH operation requires more clock cycles than a POP operation, which oneof the following options is the correct reason for this?a)For POP, the data transceivers remain in the same direction as for instruction fetch (memory to processor), whereas for PUSH their direction has to be reversedb)Memory write operations are slower than memory read operations in an 8085 bases system.c)The stack pointer needs to be pre-determined before writing registers in a PUSH, whereas aPOP operation uses the address already in the stack pointer.d)Order of register has to be interchanged for a PUSH operation, whereas POP uses their natural order.Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a 8085 system, a PUSH operation requires more clock cycles than a POP operation, which oneof the following options is the correct reason for this?a)For POP, the data transceivers remain in the same direction as for instruction fetch (memory to processor), whereas for PUSH their direction has to be reversedb)Memory write operations are slower than memory read operations in an 8085 bases system.c)The stack pointer needs to be pre-determined before writing registers in a PUSH, whereas aPOP operation uses the address already in the stack pointer.d)Order of register has to be interchanged for a PUSH operation, whereas POP uses their natural order.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a 8085 system, a PUSH operation requires more clock cycles than a POP operation, which oneof the following options is the correct reason for this?a)For POP, the data transceivers remain in the same direction as for instruction fetch (memory to processor), whereas for PUSH their direction has to be reversedb)Memory write operations are slower than memory read operations in an 8085 bases system.c)The stack pointer needs to be pre-determined before writing registers in a PUSH, whereas aPOP operation uses the address already in the stack pointer.d)Order of register has to be interchanged for a PUSH operation, whereas POP uses their natural order.Correct answer is option 'C'. Can you explain this answer?.
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