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Suppose we have a block-addressable disk drive. With such block-organized disk nondata overhead of subblocks and interblock gaps have to be accounted for. There are 40000 bytes per track and the amount of space taken up/by subblocks and interblocks gaps equivalent to 250 bytes per block. A file contains records and record size is 200 bytes to be stored on the disk, if a total of 32 blocks can be stored per track then what is the blocking factor? The term "blocking factor” is used to indicate the number of records that are to the stored in each block in a file. A block is organized to hold an integral number of logical records.
  • a)
    3
  • b)
    4
  • c)
    5
  • d)
    6
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Suppose we have a block-addressable disk drive. With such block-organi...
"blocking factor" refers to the number of records that can fit into a single block.

First, we need to calculate the actual amount of usable space per block:
40000 bytes per track - 250 bytes per block of nondata overhead = 39750 bytes per track
39750 bytes per track / 32 blocks per track = 1242.1875 bytes per block

Next, we calculate the blocking factor:
Each block can hold 1242.1875 bytes / 200 bytes per record = 6.2109375 records per block
Rounding down to the nearest integer, the blocking factor is 6 records per block.
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Suppose we have a block-addressable disk drive. With such block-organized disk nondata overhead of subblocks and interblock gaps have to be accounted for. There are 40000 bytes per track and the amount of space taken up/by subblocks and interblocks gaps equivalent to250 bytes per block. A file contains records and record size is 200 bytes to be stored on the disk, if a total of 32 blocks can be stored per track then what is the blocking factor? The term "blocking factor” is used to indicate the number of records that are to the stored in each block in a file. A block is organized to hold an integral number of logical records.a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer?
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Suppose we have a block-addressable disk drive. With such block-organized disk nondata overhead of subblocks and interblock gaps have to be accounted for. There are 40000 bytes per track and the amount of space taken up/by subblocks and interblocks gaps equivalent to250 bytes per block. A file contains records and record size is 200 bytes to be stored on the disk, if a total of 32 blocks can be stored per track then what is the blocking factor? The term "blocking factor” is used to indicate the number of records that are to the stored in each block in a file. A block is organized to hold an integral number of logical records.a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Suppose we have a block-addressable disk drive. With such block-organized disk nondata overhead of subblocks and interblock gaps have to be accounted for. There are 40000 bytes per track and the amount of space taken up/by subblocks and interblocks gaps equivalent to250 bytes per block. A file contains records and record size is 200 bytes to be stored on the disk, if a total of 32 blocks can be stored per track then what is the blocking factor? The term "blocking factor” is used to indicate the number of records that are to the stored in each block in a file. A block is organized to hold an integral number of logical records.a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose we have a block-addressable disk drive. With such block-organized disk nondata overhead of subblocks and interblock gaps have to be accounted for. There are 40000 bytes per track and the amount of space taken up/by subblocks and interblocks gaps equivalent to250 bytes per block. A file contains records and record size is 200 bytes to be stored on the disk, if a total of 32 blocks can be stored per track then what is the blocking factor? The term "blocking factor” is used to indicate the number of records that are to the stored in each block in a file. A block is organized to hold an integral number of logical records.a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer?.
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