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The velocity of propagation of electromagnetic wave in an underground cable with relative permittivity of 9 is
  • a)
    3 ×108 m/sec
  • b)
    1 × 108 m/sec
  • c)
    0.33 × 108 m/sec
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
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The velocity of propagation of an electromagnetic wave in a medium with relative permittivity εr is given by the equation:

v = c/√(εr)

where v is the velocity of propagation and c is the speed of light in vacuum.

In this case, the relative permittivity is 9, so the equation becomes:

v = c/√(9)

Simplifying this equation gives:

v = c/3

Therefore, the velocity of propagation of the electromagnetic wave in the underground cable is one-third (1/3) of the speed of light in vacuum.
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