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In a twin-wire transmission line in air, the adjacent voltage maxima are at 12 cm and 18 cm. The operating frequency is.
- a)2.5 GHz
- b)1.25 GHz
- c)5 GHz
- d)10 GHz
Correct answer is option 'A'. Can you explain this answer?
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In a twin-wire transmission line in air, the adjacent voltage maxima a...
Adjacent maxima appear with a distance of 
f = 2.5 GHZ
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f = 2.5 GHZ
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In a twin-wire transmission line in air, the adjacent voltage maxima a...
Given:
Adjacent voltage maxima at 12 cm and 18 cm
Operating frequency is to be found out.
To find the operating frequency of the twin-wire transmission line in air, we can use the formula:
λ = 2d/n
where λ is the wavelength, d is the distance between the adjacent voltage maxima and n is the number of half-wavelengths between them.
Calculating n:
n = (18 - 12) / λ/2
n = 3λ/2
n = 3/4 wavelength
Substituting the value of n in the above formula, we get:
λ = 2d/(3/4)
λ = 8d/3
The operating frequency can be calculated using the formula:
f = c/λ
where f is the frequency, c is the speed of light and λ is the wavelength.
Substituting the value of λ in the above formula, we get:
f = c/(8d/3)
f = 3c/8d
Given that the twin-wire transmission line is in air, the speed of light can be taken as 3 x 10^8 m/s.
Substituting the value of c and d in the above formula, we get:
f = 3 x 10^8 / (8 x 0.12)
f = 2.5 GHz
Therefore, the operating frequency of the twin-wire transmission line in air is 2.5 GHz.
Adjacent voltage maxima at 12 cm and 18 cm
Operating frequency is to be found out.
To find the operating frequency of the twin-wire transmission line in air, we can use the formula:
λ = 2d/n
where λ is the wavelength, d is the distance between the adjacent voltage maxima and n is the number of half-wavelengths between them.
Calculating n:
n = (18 - 12) / λ/2
n = 3λ/2
n = 3/4 wavelength
Substituting the value of n in the above formula, we get:
λ = 2d/(3/4)
λ = 8d/3
The operating frequency can be calculated using the formula:
f = c/λ
where f is the frequency, c is the speed of light and λ is the wavelength.
Substituting the value of λ in the above formula, we get:
f = c/(8d/3)
f = 3c/8d
Given that the twin-wire transmission line is in air, the speed of light can be taken as 3 x 10^8 m/s.
Substituting the value of c and d in the above formula, we get:
f = 3 x 10^8 / (8 x 0.12)
f = 2.5 GHz
Therefore, the operating frequency of the twin-wire transmission line in air is 2.5 GHz.
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In a twin-wire transmission line in air, the adjacent voltage maxima are at 12 cm and 18 cm. The operating frequency is.a)2.5 GHzb)1.25 GHzc)5 GHzd)10 GHzCorrect answer is option 'A'. Can you explain this answer?
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