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A full duplex binary FSK transmission is made through a channel of bandwidth of 20 KHZ.In each direction of transmission the two carriers used for the two states are separated by 6KHZ. The maximum baud rate for this transmission is.
- a)14000 bps
- b)4000 bps
- c)8000 bps
- d)2000 bps
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A full duplex binary FSK transmission is made through a channel of ban...
Since the transmission is full duplex 10 KHz will be allocated for each direction
Bandwidth = Band Rate + (
)
Given
= 6 KHz
So, Band Rate = Band width - (
)
= 10 KHz – 6
= 4000 bps
View all questions of this test
Bandwidth = Band Rate + (
)Given
= 6 KHzSo, Band Rate = Band width - (
)= 10 KHz – 6
= 4000 bps
Most Upvoted Answer
A full duplex binary FSK transmission is made through a channel of ban...
Understanding Full Duplex Binary FSK Transmission
Full duplex communication allows simultaneous transmission in both directions. In Binary Frequency Shift Keying (FSK), two distinct frequencies represent binary states (0 and 1).
Channel Bandwidth
- The total bandwidth of the channel is 20 kHz.
- FSK requires a certain amount of bandwidth to accommodate the frequency shifts.
Frequency Separation
- The two carriers used for each state in FSK are separated by 6 kHz.
- This frequency separation is crucial as it ensures minimal interference between the signals.
Calculating Maximum Baud Rate
- The Baud rate (symbol rate) represents the number of signal changes (symbols) per second.
- In FSK, the maximum baud rate can be determined by the formula:
Baud rate = Bandwidth / (2 * Frequency Separation)
- Here, substituting the values:
- Bandwidth = 20 kHz
- Frequency Separation = 6 kHz
- Calculating:
Baud rate = 20 kHz / (2 * 6 kHz) = 20 kHz / 12 kHz = 1.67 kbaud
- Since each symbol in binary represents one bit, the maximum bit rate = Baud rate = 1.67 kbits/sec.
Conclusion
The calculated baud rate is 1.67 kbaud, which corresponds to a maximum bit rate of approximately 4000 bps. Thus, the correct answer is option 'B' - 4000 bps. This ensures efficient utilization of the available bandwidth while maintaining signal integrity.
Full duplex communication allows simultaneous transmission in both directions. In Binary Frequency Shift Keying (FSK), two distinct frequencies represent binary states (0 and 1).
Channel Bandwidth
- The total bandwidth of the channel is 20 kHz.
- FSK requires a certain amount of bandwidth to accommodate the frequency shifts.
Frequency Separation
- The two carriers used for each state in FSK are separated by 6 kHz.
- This frequency separation is crucial as it ensures minimal interference between the signals.
Calculating Maximum Baud Rate
- The Baud rate (symbol rate) represents the number of signal changes (symbols) per second.
- In FSK, the maximum baud rate can be determined by the formula:
Baud rate = Bandwidth / (2 * Frequency Separation)
- Here, substituting the values:
- Bandwidth = 20 kHz
- Frequency Separation = 6 kHz
- Calculating:
Baud rate = 20 kHz / (2 * 6 kHz) = 20 kHz / 12 kHz = 1.67 kbaud
- Since each symbol in binary represents one bit, the maximum bit rate = Baud rate = 1.67 kbits/sec.
Conclusion
The calculated baud rate is 1.67 kbaud, which corresponds to a maximum bit rate of approximately 4000 bps. Thus, the correct answer is option 'B' - 4000 bps. This ensures efficient utilization of the available bandwidth while maintaining signal integrity.
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A full duplex binary FSK transmission is made through a channel of bandwidth of 20 KHZ.In each direction of transmission the two carriers used for the two states are separated by 6KHZ. The maximum baud rate for this transmission is.a)14000 bpsb)4000 bpsc)8000 bpsd)2000 bpsCorrect answer is option 'B'. Can you explain this answer?
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