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An amplifier using BJT has two identical stages each having a lower cut-off (3dB) frequency of 64Hz due to coupling capacitor. The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz. The lower 3dB frequency of the overall amplifier is nearly
- a)128 Hz
- b)100 Hz
- c)41 Hz
- d)156 Hz
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
An amplifier using BJT has two identical stages each having a lower cu...
So overall lower cut-off frequency,
= 100 Hz
= 100 Hz
Most Upvoted Answer
An amplifier using BJT has two identical stages each having a lower cu...
Given Information:
- An amplifier using BJT has two identical stages.
- Each stage has a lower cut-off (3dB) frequency of 64Hz due to a coupling capacitor.
- The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz.
To find:
The lower 3dB frequency of the overall amplifier.
Solution:
Lower Cut-off Frequency due to Coupling Capacitor:
The lower cut-off frequency due to the coupling capacitor can be calculated using the formula:
f_c = 1 / (2π * R * C)
Where:
- f_c is the cut-off frequency
- R is the resistance
- C is the capacitance
Since the two stages are identical, the cut-off frequency due to the coupling capacitor for each stage is the same. So, the cut-off frequency for each stage is 64Hz.
Lower Cut-off Frequency due to Emitter Bypass Capacitor:
The lower cut-off frequency due to the emitter bypass capacitor can be calculated using the formula:
f_c = 1 / (2π * R * C)
Where:
- f_c is the cut-off frequency
- R is the resistance
- C is the capacitance
Since the two stages are identical, the cut-off frequency due to the emitter bypass capacitor for each stage is the same. So, the cut-off frequency for each stage is 64Hz.
Overall Lower Cut-off Frequency:
When two stages are cascaded, their cut-off frequencies get multiplied. So, the overall lower cut-off frequency of the amplifier is:
f_total = f_stage1 * f_stage2
f_total = 64Hz * 64Hz
f_total = 4096Hz
Approximation:
The closest option to 4096Hz is 100Hz, which is option 'B'.
- An amplifier using BJT has two identical stages.
- Each stage has a lower cut-off (3dB) frequency of 64Hz due to a coupling capacitor.
- The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz.
To find:
The lower 3dB frequency of the overall amplifier.
Solution:
Lower Cut-off Frequency due to Coupling Capacitor:
The lower cut-off frequency due to the coupling capacitor can be calculated using the formula:
f_c = 1 / (2π * R * C)
Where:
- f_c is the cut-off frequency
- R is the resistance
- C is the capacitance
Since the two stages are identical, the cut-off frequency due to the coupling capacitor for each stage is the same. So, the cut-off frequency for each stage is 64Hz.
Lower Cut-off Frequency due to Emitter Bypass Capacitor:
The lower cut-off frequency due to the emitter bypass capacitor can be calculated using the formula:
f_c = 1 / (2π * R * C)
Where:
- f_c is the cut-off frequency
- R is the resistance
- C is the capacitance
Since the two stages are identical, the cut-off frequency due to the emitter bypass capacitor for each stage is the same. So, the cut-off frequency for each stage is 64Hz.
Overall Lower Cut-off Frequency:
When two stages are cascaded, their cut-off frequencies get multiplied. So, the overall lower cut-off frequency of the amplifier is:
f_total = f_stage1 * f_stage2
f_total = 64Hz * 64Hz
f_total = 4096Hz
Approximation:
The closest option to 4096Hz is 100Hz, which is option 'B'.
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An amplifier using BJT has two identical stages each having a lower cut-off (3dB) frequency of 64Hz due to coupling capacitor. The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz. The lower 3dB frequency of the overall amplifier is nearlya)128 Hzb)100 Hzc)41 Hzd)156 HzCorrect answer is option 'B'. Can you explain this answer?
Question Description
An amplifier using BJT has two identical stages each having a lower cut-off (3dB) frequency of 64Hz due to coupling capacitor. The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz. The lower 3dB frequency of the overall amplifier is nearlya)128 Hzb)100 Hzc)41 Hzd)156 HzCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An amplifier using BJT has two identical stages each having a lower cut-off (3dB) frequency of 64Hz due to coupling capacitor. The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz. The lower 3dB frequency of the overall amplifier is nearlya)128 Hzb)100 Hzc)41 Hzd)156 HzCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An amplifier using BJT has two identical stages each having a lower cut-off (3dB) frequency of 64Hz due to coupling capacitor. The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz. The lower 3dB frequency of the overall amplifier is nearlya)128 Hzb)100 Hzc)41 Hzd)156 HzCorrect answer is option 'B'. Can you explain this answer?.
An amplifier using BJT has two identical stages each having a lower cut-off (3dB) frequency of 64Hz due to coupling capacitor. The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz. The lower 3dB frequency of the overall amplifier is nearlya)128 Hzb)100 Hzc)41 Hzd)156 HzCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An amplifier using BJT has two identical stages each having a lower cut-off (3dB) frequency of 64Hz due to coupling capacitor. The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz. The lower 3dB frequency of the overall amplifier is nearlya)128 Hzb)100 Hzc)41 Hzd)156 HzCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An amplifier using BJT has two identical stages each having a lower cut-off (3dB) frequency of 64Hz due to coupling capacitor. The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz. The lower 3dB frequency of the overall amplifier is nearlya)128 Hzb)100 Hzc)41 Hzd)156 HzCorrect answer is option 'B'. Can you explain this answer?.
Solutions for An amplifier using BJT has two identical stages each having a lower cut-off (3dB) frequency of 64Hz due to coupling capacitor. The emitter bypass capacitor also provides a lower cut-off (3dB) frequency due to emitter degeneration alone of 64Hz. The lower 3dB frequency of the overall amplifier is nearlya)128 Hzb)100 Hzc)41 Hzd)156 HzCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
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