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What would be the relative population of the J = 1 and J = 0 rotational states of HCl at 25°C_______?               
(Given: BHCl = 10.591 cm–1) [Rounded up to first decimal place]
    Correct answer is between '2.6,2.8'. Can you explain this answer?
    Most Upvoted Answer
    What would be the relative population of the J = 1 and J = 0 rotationa...
    °C if the total number of molecules in the sample is 1.00 × 10^16?

    To determine the relative population of the J = 1 and J = 0 rotational states of HCl at 25°C, we can use the Boltzmann distribution equation:

    N(J)/N = (2J + 1) exp(-E(J)/kT)

    where N(J) is the number of molecules in the J rotational state, N is the total number of molecules in the sample, E(J) is the energy of the J rotational state, k is the Boltzmann constant, and T is the temperature in Kelvin.

    For HCl, the energy of the J = 1 rotational state is E(1) = (1/2)hB, where h is the Planck constant and B is the rotational constant. The energy of the J = 0 rotational state is E(0) = 0.

    At 25°C, T = 298 K. The rotational constant of HCl is B = 10.593 cm^-1.

    Plugging in the values, we get:

    N(1)/N = 3 exp(-E(1)/kT) = 3 exp(-hB/2kT) = 3 exp(-2.93)

    N(0)/N = 1 exp(-E(0)/kT) = 1 exp(0) = 1

    Thus, the relative population of the J = 1 and J = 0 rotational states of HCl at 25°C would be:

    N(1)/N(0) = 3 exp(-2.93) = 0.003

    This means that the J = 1 state is only about 0.3% as populated as the J = 0 state at 25°C.
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    What would be the relative population of the J = 1 and J = 0 rotational states of HCl at 25°C_______? (Given: BHCl = 10.591 cm–1) [Rounded up to first decimal place]Correct answer is between '2.6,2.8'. Can you explain this answer?
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    What would be the relative population of the J = 1 and J = 0 rotational states of HCl at 25°C_______? (Given: BHCl = 10.591 cm–1) [Rounded up to first decimal place]Correct answer is between '2.6,2.8'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about What would be the relative population of the J = 1 and J = 0 rotational states of HCl at 25°C_______? (Given: BHCl = 10.591 cm–1) [Rounded up to first decimal place]Correct answer is between '2.6,2.8'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What would be the relative population of the J = 1 and J = 0 rotational states of HCl at 25°C_______? (Given: BHCl = 10.591 cm–1) [Rounded up to first decimal place]Correct answer is between '2.6,2.8'. Can you explain this answer?.
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