An electron in a metal encounters a barrier layer of height 6eVand thi...
We know,
With E = 5eV and V
0 = 16eV
With
a = 0.5 × 10
–9 m,
m = 9.1 × 10
–31 kg,
V0 = 6
eV,
E = 5
V and
Hence the percentage of probability of tunneling is 1.33.
The correct answer is: 1.33
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An electron in a metal encounters a barrier layer of height 6eVand thi...
Probability of Tunneling through a Barrier
Given:
- Height of the barrier, V = 6 eV
- Thickness of the barrier, d = 0.5 nm
- Electron energy, E = 5 eV
To find the probability of tunneling through the barrier, we can use the concept of quantum tunneling. Quantum tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even if its energy is less than the height of the barrier.
The transmission probability, T, can be calculated using the following equation:
T = exp(-2κd)
where κ is the decay constant, given by:
κ = sqrt((2m/h_bar^2)(V - E))
Here, m is the mass of the electron and h_bar is the reduced Planck's constant.
Calculating the Decay Constant (κ)
Let's calculate the decay constant κ using the given values:
m = mass of an electron = 9.1 x 10^-31 kg
h_bar = reduced Planck's constant = 6.626 x 10^-34 J s / (2π)
V = 6 eV = 6 x 1.6 x 10^-19 J
E = 5 eV = 5 x 1.6 x 10^-19 J
κ = sqrt((2m/h_bar^2)(V - E))
= sqrt((2 * 9.1 x 10^-31 kg) / ((6.626 x 10^-34 J s / (2π))^2) * (6 x 1.6 x 10^-19 J - 5 x 1.6 x 10^-19 J))
≈ 1.29 x 10^10 m^-1
Calculating the Transmission Probability (T)
Now, let's calculate the transmission probability using the decay constant κ and the thickness of the barrier d:
T = exp(-2κd)
= exp(-2 * 1.29 x 10^10 m^-1 * 0.5 x 10^-9 m)
≈ 1.33
Therefore, the probability of the electron tunneling through the barrier is approximately 1.33.
This means that there is a high likelihood that the electron will tunnel through the barrier, despite its energy being less than the height of the barrier. Quantum tunneling allows particles to overcome energy barriers and exhibit wave-like behavior, enabling them to pass through regions that classically would be considered impenetrable.