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3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL ofthis solution is now taken is another containermLof 5M NaOH is added to this.Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)Correct answer is '5.22'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL ofthis solution is now taken is another containermLof 5M NaOH is added to this.Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)Correct answer is '5.22'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL ofthis solution is now taken is another containermLof 5M NaOH is added to this.Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)Correct answer is '5.22'. Can you explain this answer?.

Solutions for 3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL ofthis solution is now taken is another containermLof 5M NaOH is added to this.Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)Correct answer is '5.22'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of 3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL ofthis solution is now taken is another containermLof 5M NaOH is added to this.Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)Correct answer is '5.22'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of 3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL ofthis solution is now taken is another containermLof 5M NaOH is added to this.Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)Correct answer is '5.22'. Can you explain this answer?, a detailed solution for 3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL ofthis solution is now taken is another containermLof 5M NaOH is added to this.Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)Correct answer is '5.22'. Can you explain this answer? has been provided alongside types of 3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL ofthis solution is now taken is another containermLof 5M NaOH is added to this.Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)Correct answer is '5.22'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice 3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL ofthis solution is now taken is another containermLof 5M NaOH is added to this.Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)Correct answer is '5.22'. Can you explain this answer? tests, examples and also practice JEE tests.