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Among the following complexes, the ones that show(s) chirality are:
I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-
I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-
- a)I, III, IV
- b)I, II, III
- c)II, III, IV
- d)I, II, IV
Correct answer is option 'D'. Can you explain this answer?
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Among the following complexes, the ones that show(s) chirality are:I =...
Chirality in Complexes
Chirality is a property of a molecule that cannot be superimposed on its mirror image. In other words, a chiral molecule exists in two forms that are non-superimposable mirror images of each other, called enantiomers. Chirality can arise in coordination compounds if they have a central metal atom that is surrounded by different ligands in a specific arrangement.
Identification of Chirality in Complexes
To determine whether a coordination compound is chiral or not, we need to examine its structure and symmetry elements. Chirality is only possible if the molecule has no rotational symmetry, meaning that it cannot be rotated by any angle and still look the same. The presence of an axis of symmetry or a plane of symmetry indicates that the molecule is achiral.
Applying the above principles, we can identify the chiral complexes among the given options:
I = [Ru(bipyridyl)3]: This complex has three bipyridyl ligands arranged symmetrically around the central ruthenium atom. It has a plane of symmetry that divides the molecule into mirror images, making it achiral.
II = [Cr(EDTA)]-: This complex has a central chromium atom surrounded by four oxygen atoms and two nitrogen atoms of the EDTA ligand. It has a plane of symmetry that divides the molecule into mirror images, making it achiral.
III = trans[Cr(Cl)2(oxalate)2]3-: This complex has a central chromium atom surrounded by two chloride ions and two oxalate ligands arranged trans to each other. It has no symmetry elements, making it chiral.
IV = cis[Cr(Cl)2(oxalate)2]3-: This complex has a central chromium atom surrounded by two chloride ions and two oxalate ligands arranged cis to each other. It has no symmetry elements, making it chiral.
Therefore, the complexes that show chirality are I, II, and IV. The correct option is D.
Chirality is a property of a molecule that cannot be superimposed on its mirror image. In other words, a chiral molecule exists in two forms that are non-superimposable mirror images of each other, called enantiomers. Chirality can arise in coordination compounds if they have a central metal atom that is surrounded by different ligands in a specific arrangement.
Identification of Chirality in Complexes
To determine whether a coordination compound is chiral or not, we need to examine its structure and symmetry elements. Chirality is only possible if the molecule has no rotational symmetry, meaning that it cannot be rotated by any angle and still look the same. The presence of an axis of symmetry or a plane of symmetry indicates that the molecule is achiral.
Applying the above principles, we can identify the chiral complexes among the given options:
I = [Ru(bipyridyl)3]: This complex has three bipyridyl ligands arranged symmetrically around the central ruthenium atom. It has a plane of symmetry that divides the molecule into mirror images, making it achiral.
II = [Cr(EDTA)]-: This complex has a central chromium atom surrounded by four oxygen atoms and two nitrogen atoms of the EDTA ligand. It has a plane of symmetry that divides the molecule into mirror images, making it achiral.
III = trans[Cr(Cl)2(oxalate)2]3-: This complex has a central chromium atom surrounded by two chloride ions and two oxalate ligands arranged trans to each other. It has no symmetry elements, making it chiral.
IV = cis[Cr(Cl)2(oxalate)2]3-: This complex has a central chromium atom surrounded by two chloride ions and two oxalate ligands arranged cis to each other. It has no symmetry elements, making it chiral.
Therefore, the complexes that show chirality are I, II, and IV. The correct option is D.
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Among the following complexes, the ones that show(s) chirality are:I =...
If in a complex centre of or plane of symmetry or alternating axis of symmetry is present then the complex will be optically inactive i.e, achiral. Alternatively if a complex and its Mirror image is super impossible with each other, it will be achiral. The complex I and Il has none of the symmetry elements mentioned above, hence these are achiral. The complex lV is also due to the same reason is chiral. But the complex lll is optically inactive i.e, achiral due to the presence of centre of inversion. As the complex lll and its mirror image are super impossible to each other complex lll is a chiral.
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Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer?
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Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer?.
Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Among the following complexes, the ones that show(s) chirality are:I = [Ru(bipyridyl)3]+, II = [Cr(EDTA)]-, III = trans[Cr(Cl)2(oxalate)2]3-, IV = cis[Cr(Cl)2(oxalate)2]3-a)I, III, IVb)I, II, III c)II, III, IVd)I, II, IVCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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