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In a hydrogen atom, the ratio of the wavelengths of lyman-α radiation (in n = 2 to n =1) to Balmer-α radiation (n = 3 → n = 2) is
  • a)
    4/3
  • b)
     5/27
  • c)
    5/48
  • d)
    27/5
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In a hydrogen atom, the ratio of the wavelengths of lyman-αradia...
Solution:

Rydberg formula:



λvac = the wavelength of the light emitted in vacuum
RH = Rydberg constant for Hydrogen
n1 and n2 are integers such that 

For Lyman-radiation (n = 2 → n = 1):



For Balmer-radiation (n = 3 → n = 2):



The Ratio:



Answer: B
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Most Upvoted Answer
In a hydrogen atom, the ratio of the wavelengths of lyman-αradia...
Transition to n=1 and n=2 are refered to as Lyman and Balmer series.

For Lyman Series wavelength will be longest when energy the electron has transition from n=2 to n=1 level.
For Balmer  Series wavelength will be longest when  energy the electron has transition from n=3 to n=2 level.
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In a hydrogen atom, the ratio of the wavelengths of lyman-αradiation (inn= 2 ton=1) to Balmer-αradiation (n= 3→n= 2) isa)4/3b)5/27c)5/48d)27/5Correct answer is option 'B'. Can you explain this answer?
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