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On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is _____
(Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol–1 and 5.12 K kg mol–1, respectively)
    Correct answer is between '1.02,1.03'. Can you explain this answer?
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    On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benz...
    To find the depression of freezing point, we can use the equation:

    ΔTf = i * Kf * m

    Where:
    ΔTf = depression of freezing point
    i = Van't Hoff factor (for a non-ionic solute, i = 1)
    Kf = molal freezing point depression constant of benzene (5.12 K kg mol^-1)
    m = molality of the solution

    First, we need to calculate the molality of the solution:

    Molar mass of solute = 0.5 g mol^-1
    Moles of solute = 0.5 g / molar mass = 0.5 g / 78 g mol^-1 = 0.00641 mol
    Moles of benzene = 39 g / 78 g mol^-1 = 0.5 mol

    molality (m) = moles of solute / mass of solvent in kg
    m = 0.00641 mol / 0.039 kg = 0.1644 mol kg^-1

    Now we can calculate the depression of freezing point:

    ΔTf = 1 * 5.12 K kg mol^-1 * 0.1644 mol kg^-1
    ΔTf = 0.839 K

    Therefore, the depression of freezing point of benzene upon addition of the solute is 0.839 K.
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    On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is _____(Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol–1 and 5.12 K kg mol–1, respectively)Correct answer is between '1.02,1.03'. Can you explain this answer?
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    On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is _____(Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol–1 and 5.12 K kg mol–1, respectively)Correct answer is between '1.02,1.03'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is _____(Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol–1 and 5.12 K kg mol–1, respectively)Correct answer is between '1.02,1.03'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is _____(Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol–1 and 5.12 K kg mol–1, respectively)Correct answer is between '1.02,1.03'. Can you explain this answer?.
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