A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + andDelta;f when n1 = n and n2 = n + andDelta;n. Assuming andDelta;n andlt;andlt; (nandndash;1) and 1 andlt; n andlt; 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, andDelta;n = 10andndash;3 and f = 20 cm, the value of -andDelta;f- will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer?

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A thin convex lens is made of two materials with refractive indices n₁ and n₂, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n₁ = n₂ = n. The focal length is f + Δf when n₁ = n and n₂ = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:

a)
The relation between remains unchanged if both the convex surfaces are replaced by concave surfaces of the same radius of curvature.
b)
c)
For n = 1.5, Δn = 10^–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2^nd decimal place)
d)

Correct answer is option 'A,C,D'. Can you explain this answer?

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A thin convex lens is made of two materials with refractive indices n1...

when n₁ = n₂ = n

...(1)
2^nd case:

...(2)
(1) Relation between

is independent of R so (1) is correct.
(2) 2n – 2 < n because n < 2

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A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n – 1) and 1 < n < 2. The correct statement(s) is/are.

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Statement-1 : A spherical surface of radius of curvature R separates two media of refractive index n1 and n2 as shown. If an object O (a thin small ro d) is placed upright on principal axis at a distance R from pole (i.e, placed at centre of curvatur e), then the size of image is same as size of object.Statement-2 : If a point object is placed at centre of curvature of spherical surface separating two media of different refractive index, then the image is also formed at centre of curvature, i.e., image distance is equal to object distance.

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The radius of curvature of spherical surface is 10 cm. The spherical surface separates two media of refractive indices μ2= 1.3 and μ3= 1.5 as shown inFigure. The medium of refractive index 1.3 extends upto 78 cm from the spherical surface. A luminous point object O is at the distance of 144 cm from the spherical surface in the medium of refractive index μ1= 1.1. The image formed by the spherical surface is at

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Most materials have the refractive index, n > 1. So, when a light ray from air enters a naturally occurring material, then by Snell’slaw,it is understood that the refracted ray bends towards the normal. But it never emerges on the same side of the normal as the incident ray. According to electromagnetism, the refractive index of the medium is given by the relation,n= c /where c is the speed of electromagnetic waves in vacuum, v its speed in the medium, εr and μr are the relative permittivity and permeability of the medium respectively.In normal materials, both εr and μr , are positive, implying positive n for the medium. When both εr and μr are negative, one must choose the negative root of n. Such negative refractive index materials can now be artificially prepared and are called metamaterials. They exhibit significantly different optical behavior, without violating any physical laws. Since n is negative, it results in a change in the direction of propagation of the refracted light.However, similar to normal materials, the frequency of light remains unchanged upon refraction even in meta-materials. Q.Choose the correct statement.

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Paragraph for Questions 13 and 14Most materials have the refractive index, n > 1. So, when a light ray from air enters a naturally occurringmaterial, then by Snell’s law, it is understood that the refracted ray bends towards the normal.But it never emerges on the same side of the normal as the incident ray. According to electromagnetism,the refractive index of the medium is given by the relation, where c is the speed ofelectromagnetic waves in vacuum, v its speed in the medium, εr and μr are the relative permittivity andpermeability of the medium respectively.In normal materials, both εr and μr, are positive, implying positive n for the medium. When both εr and μrare negative, one must choose the negative root of n. Such negative refractive index materials can nowbe artificially prepared and are called meta-materials. They exhibit significantly different optical behavior,without violating any physical laws. Since n is negative, it results in a change in the direction ofpropagation of the refracted light. However, similar to normal materials, the frequency of light remainsunchanged upon refraction even in meta-materials.Q.Choose the correct statement.

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A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer?

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A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer?.

Solutions for A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer?, a detailed solution for A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer? has been provided alongside types of A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A thin convex lens is made of two materials with refractive indices n1 and n2, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1 = n2 = n. The focal length is f + Δf when n1 = n and n2 = n + Δn. Assuming Δn << (n–1) and 1 < n < 2, the correct statement(s) is/are:a)The relation betweenremains unchanged if both the convex surfaces are replaced byconcave surfaces of the same radius of curvature.b)c)For n = 1.5, Δn = 10–3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd decimal place)d)Correct answer is option 'A,C,D'. Can you explain this answer? tests, examples and also practice JEE tests.

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