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In a population of 100 humans 4 show fuse Ear lobe , if it is autosomal recessive character and population is in genetic equlilibrium calculate frequency of dominant allele -
- a)0.8
- b)0.6
- c)0.06
- d)0.2
Correct answer is option 'A'. Can you explain this answer?
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Ina population of 100 humans4show fuse Ear lobe , if it is autosomal r...
hardy Weinberg problem
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Ina population of 100 humans4show fuse Ear lobe , if it is autosomal r...
Genetic Equilibrium
The Hardy-Weinberg principle states that in a large, randomly mating population with no mutation, migration, or selection, the frequencies of alleles and genotypes will remain constant from generation to generation. This is known as genetic equilibrium.
Autosomal Recessive Trait
An autosomal recessive trait is a trait that is expressed only when an individual is homozygous for the recessive allele. In this case, individuals with the dominant allele will not show the trait.
Calculating Allele Frequencies
In this population, the frequency of the recessive allele can be calculated using the following formula:
q^2 + 2pq + p^2 = 1
where q is the frequency of the recessive allele and p is the frequency of the dominant allele.
Given that 4 individuals show the trait, it can be assumed that they are homozygous recessive. Therefore:
q^2 = 4/100
q = 0.2
Substituting q into the equation:
p = 1 - q
p = 1 - 0.2
p = 0.8
Therefore, the frequency of the dominant allele is 0.8.
Answer: a) 0.8
The Hardy-Weinberg principle states that in a large, randomly mating population with no mutation, migration, or selection, the frequencies of alleles and genotypes will remain constant from generation to generation. This is known as genetic equilibrium.
Autosomal Recessive Trait
An autosomal recessive trait is a trait that is expressed only when an individual is homozygous for the recessive allele. In this case, individuals with the dominant allele will not show the trait.
Calculating Allele Frequencies
In this population, the frequency of the recessive allele can be calculated using the following formula:
q^2 + 2pq + p^2 = 1
where q is the frequency of the recessive allele and p is the frequency of the dominant allele.
Given that 4 individuals show the trait, it can be assumed that they are homozygous recessive. Therefore:
q^2 = 4/100
q = 0.2
Substituting q into the equation:
p = 1 - q
p = 1 - 0.2
p = 0.8
Therefore, the frequency of the dominant allele is 0.8.
Answer: a) 0.8
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Ina population of 100 humans4show fuse Ear lobe , if it is autosomal recessive character and population is in genetic equlilibrium calculate frequency of dominant allele -a)0.8b)0.6c)0.06d)0.2Correct answer is option 'A'. Can you explain this answer?
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Ina population of 100 humans4show fuse Ear lobe , if it is autosomal recessive character and population is in genetic equlilibrium calculate frequency of dominant allele -a)0.8b)0.6c)0.06d)0.2Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ina population of 100 humans4show fuse Ear lobe , if it is autosomal recessive character and population is in genetic equlilibrium calculate frequency of dominant allele -a)0.8b)0.6c)0.06d)0.2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ina population of 100 humans4show fuse Ear lobe , if it is autosomal recessive character and population is in genetic equlilibrium calculate frequency of dominant allele -a)0.8b)0.6c)0.06d)0.2Correct answer is option 'A'. Can you explain this answer?.
Ina population of 100 humans4show fuse Ear lobe , if it is autosomal recessive character and population is in genetic equlilibrium calculate frequency of dominant allele -a)0.8b)0.6c)0.06d)0.2Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ina population of 100 humans4show fuse Ear lobe , if it is autosomal recessive character and population is in genetic equlilibrium calculate frequency of dominant allele -a)0.8b)0.6c)0.06d)0.2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ina population of 100 humans4show fuse Ear lobe , if it is autosomal recessive character and population is in genetic equlilibrium calculate frequency of dominant allele -a)0.8b)0.6c)0.06d)0.2Correct answer is option 'A'. Can you explain this answer?.
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