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Hot water cools from 60°C to 50°C in the first 10 minutes and to 42°C in the next 10 minutes. The temperature of the surroundings is :​
  • a)
    25°C
  • b)
    10°C
  • c)
    15°C
  • d)
    20°C
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Hot water cools from 60°C to 50°C in the first 10 minutes and ...
The rate of change temperature is given as,

Substitute the values.

   ....(1)
Similarly,
   ...(2)
Thus,
T = 10 °C
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Most Upvoted Answer
Hot water cools from 60°C to 50°C in the first 10 minutes and ...
°F to 40°F in 10 minutes. The rate of cooling is given by the equation:

Rate of cooling = (Final temperature - Initial temperature) / Time

Rate of cooling = (40°F - 60°F) / 10 minutes

Rate of cooling = -2°F/minute

Therefore, the hot water cools at a rate of 2°F per minute.
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Hot water cools from 60°C to 50°C in the first 10 minutes and to 42°C in the next 10 minutes. The temperature of the surroundings is :a)25°Cb)10°Cc)15°Cd)20°CCorrect answer is option 'B'. Can you explain this answer?
Question Description
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