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An ideal monoatomic gas is taken round that cycle ABCDA as shown in the p-V diagram (see figure). The work done during the cycle is
  • a)
    2pV
  • b)
    0
  • c)
    pV
  • d)
    pv/2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
An ideal monoatomic gas is taken round that cycle ABCDA as shown in th...
Work done in a cyclic process = area under the graph in p-V diagram
Area = AB × BC = (2p – p) × (2V – V) = pV
∴ So, work done = pV
The correct answer is: pV
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Most Upvoted Answer
An ideal monoatomic gas is taken round that cycle ABCDA as shown in th...
Work done in a cyclic process = area under the graph in p-V diagram
Area = AB × BC = (2p – p) × (2V – V) = pV
∴ So, work done = pV
The correct answer is: pV
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Community Answer
An ideal monoatomic gas is taken round that cycle ABCDA as shown in th...
Work done in a cyclic process = area under the graph in p-V diagram
Area = AB × BC = (2p – p) × (2V – V) = pV
∴ So, work done = pV
The correct answer is: pV
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An ideal monoatomic gas is taken round that cycle ABCDA as shown in the p-V diagram (see figure). The work done during the cycle isa)2pVb)0c)pVd)pv/2Correct answer is option 'C'. Can you explain this answer?
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