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Two friends A and B toss 20 coins each such that the number of heads obtained by A and the number of tails obtained by B are in the ratio 7 : 4. If the number of heads obtained between both of them are 33 then find the ratio of the number of heads and tails obtained by A.
  • a)
    4 : 7
  • b)
    11 : 7
  • c)
    7 : 3
  • d)
    No possible solution
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Two friends A and B toss 20 coins each such that the number of heads o...
The total number of heads or tails obtained = 40
Out of which 33 are heads.
Therefore, the number of tails = 7
Let heads obtained by A and tails obtained by B be 7x and 4x repsectively.
Tails obtained by A = 7 - 4x
Since total coins tossed = 20
7x + 7 - 4x = 20
x = 13/3
which is not possible.
Hence, option 4.
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Most Upvoted Answer
Two friends A and B toss 20 coins each such that the number of heads o...
To solve this problem, let's assume that A gets a number of heads as 7x and B gets a number of tails as 4x.

Given that the total number of heads is 33, we can write the equation as:
7x = 33

Solving the equation, we find that x = 33/7 = 4.7

Since we cannot have a non-integer value of x, we can conclude that there is no solution to this problem. Hence, the correct answer is option 'D' - No possible solution.

Explanation:
1. Assume the number of heads obtained by A is 7x and the number of tails obtained by B is 4x.
2. The total number of heads obtained by A and B is given as 33.
3. Write the equation: 7x = 33
4. Solve the equation: x = 33/7 = 4.7
5. Since x is not an integer value, it is not possible to have a ratio of 7:4 for the number of heads and tails obtained.
6. Therefore, there is no possible solution to this problem.
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Community Answer
Two friends A and B toss 20 coins each such that the number of heads o...
The answer can't be told from the options.
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