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There are 3 children of a lady. In how many ways is it possible to dress them for a party if the first child likes 3 dresses, second likes 4 and the third likes 5 but the third child has out grown one of them? Each child has a different set of clothes. 
  • a)
    11 
  • b)
    10 
  • c)
    60 
  • d)
    48 
  • e)
    15
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
There are 3 children of a lady. In how many ways is it possible to dre...
Given:
- 3 children
- The first child likes 3 dresses
- The second child likes 4 dresses
- The third child likes 5 dresses
- The third child has outgrown one of their dresses

To find:
- Number of ways to dress the children for a party

Approach:
Since each child has a different set of clothes, we can simply multiply the number of choices for each child to get the total number of combinations. However, we need to account for the fact that the third child has outgrown one of their dresses.

- Number of choices for the first child = 3
- Number of choices for the second child = 4
- Number of choices for the third child = 4 (since they cannot wear the outgrown dress)

Total number of combinations = 3 x 4 x 4 = 48

Therefore, the correct answer is option D (48).
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Community Answer
There are 3 children of a lady. In how many ways is it possible to dre...
If all of their dresses are fit for the childs, the possible way to dress them is 3*4*5=60
But one dress is out grown for the third child. Hence below combination is not possoble
3*4*1=12
So total number of possible ways are 3*4*5-3*4*1=48
Hence the answer is option D
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There are 3 children of a lady. In how many ways is it possible to dress them for a party if the first child likes 3 dresses, second likes 4 and the third likes 5 but the third child has out grown one of them? Each child has a different set of clothes.a)11b)10c)60d)48e)15Correct answer is option 'D'. Can you explain this answer?
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