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The energy of the first excited quantum state of a particle in the two - dimensional potential v(x,y) = 2m  is 
  • a)
    3/2 hω
  • b)
    5/2 hω
  • c)
    3 hω
  • d)
    5 hω
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The energy of the first excited quantum state of a particle in the two...



for ground state energy E0 = 3 hω 
first excited energy E1 = 5 hω
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Most Upvoted Answer
The energy of the first excited quantum state of a particle in the two...



for ground state energy E0 = 3 hω 
first excited energy E1 = 5 hω
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The energy of the first excited quantum state of a particle in the two - dimensional potentialv(x,y) = 2misa)3/2 hωb)5/2 hωc)3hωd)5hωCorrect answer is option 'D'. Can you explain this answer?
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