JEE Exam > JEE Questions > Given a solution of HNO3 of density 1.4 g/mL ...
Start Learning for Free
Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.
Correct answer is '14'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine mo...
Most Upvoted Answer
Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine mo...
Explanation:
Step 1: Calculate the mass of HNO3 in 100 g solution.
Given that the solution is 63% w/w, which means 63 g of HNO3 is present in 100 g of the solution.
So, the mass of HNO3 in 1 L (1000 mL) of solution = (63/100) x 1000 = 630 g
Step 2: Use the density of the solution to calculate the volume of the solution.
1 L of HNO3 solution weighs 1.4 kg (1.4 g/mL x 1000 mL)
So, the volume of the solution = 630 g / 1.4 g/mL = 450 mL
Step 3: Calculate the molarity of HNO3 solution.
Molarity (M) = Number of moles of solute / Volume of solution in liters
Number of moles of HNO3 = Mass of HNO3 / Molecular weight of HNO3
The molecular weight of HNO3 = 1 + 14 + 48 = 63 g/mol
Number of moles of HNO3 = 630 g / 63 g/mol = 10 mol
Volume of solution in liters = 450 mL / 1000 mL/L = 0.45 L
So, Molarity (M) = 10 mol / 0.45 L = 22.22 M
Step 4: Round off the answer to the nearest integer.
Since the molarity value obtained is in decimals, it is rounded off to the nearest integer.
The correct answer is '14'.
Step 1: Calculate the mass of HNO3 in 100 g solution.
Given that the solution is 63% w/w, which means 63 g of HNO3 is present in 100 g of the solution.
So, the mass of HNO3 in 1 L (1000 mL) of solution = (63/100) x 1000 = 630 g
Step 2: Use the density of the solution to calculate the volume of the solution.
1 L of HNO3 solution weighs 1.4 kg (1.4 g/mL x 1000 mL)
So, the volume of the solution = 630 g / 1.4 g/mL = 450 mL
Step 3: Calculate the molarity of HNO3 solution.
Molarity (M) = Number of moles of solute / Volume of solution in liters
Number of moles of HNO3 = Mass of HNO3 / Molecular weight of HNO3
The molecular weight of HNO3 = 1 + 14 + 48 = 63 g/mol
Number of moles of HNO3 = 630 g / 63 g/mol = 10 mol
Volume of solution in liters = 450 mL / 1000 mL/L = 0.45 L
So, Molarity (M) = 10 mol / 0.45 L = 22.22 M
Step 4: Round off the answer to the nearest integer.
Since the molarity value obtained is in decimals, it is rounded off to the nearest integer.
The correct answer is '14'.
Free Test
FREE
| Start Free Test |
Community Answer
Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine mo...
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer?
Question Description
Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer?.
Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer?.
Solutions for Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer?, a detailed solution for Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer? has been provided alongside types of Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Determine molarity of HNO3 solution.Correct answer is '14'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup