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What is the conductivity of a semiconductor sample having electron concentration of 5×1018 m−3, hole concentration of 5×1019 m−3, electron mobility of 2.0 m2 V−1  s−1 and hole mobility of 0.01 m2 V−1 s−1?
(Take charge of electron as 1.6×10−19 C)
  • a)
    0.59 (Ω - m)−1
  • b)
    1.83 (Ω - m)−1
  • c)
    1.68 (Ω - m)−1
  • d)
    1.20 (Ω - m)−1
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What is the conductivity of a semiconductor sample having electron con...
s = e (neμe + nnμn)
= 1.6 × 10-19 (5 × 1018 × 2 + 5 × 1019 × 0.01)
= 1.6 × 10–19 (1019  + 0.05 × 1019)
= 1.6 × 1.05
= 1.68
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Most Upvoted Answer
What is the conductivity of a semiconductor sample having electron con...
The conductivity of a semiconductor sample is determined by both the electron concentration (n) and the electron mobility (μ). The formula for conductivity (σ) is given by:

σ = n * μ * q

Where:
σ = conductivity
n = electron concentration
μ = electron mobility
q = elementary charge

In order to calculate the conductivity, we need to know the value of the electron mobility. Without that information, we cannot provide a specific value for the conductivity.
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What is the conductivity of a semiconductor sample having electron concentration of 5×1018 m−3, hole concentration of 5×1019 m−3, electron mobility of 2.0 m2 V−1 s−1 and holemobility of 0.01 m2 V−1 s−1?(Take charge of electron as 1.6×10−19 C)a)0.59 ( - m)−1b)1.83 ( - m)−1c)1.68 ( - m)−1d)1.20 ( - m)−1Correct answer is option 'C'. Can you explain this answer?
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