Find the energy release (in MeV), if two nuclei can fuse together to form 42He nucleus. The binding energy per nucleon of 2H and 4He is 1.1 meV and 7.0 MeV respectively.Correct answer is '23.6'. Can you explain this answer?

Question

Find the energy release (in MeV), if two  nuclei can fuse together to form 42He nucleus. The binding energy per nucleon of 2H and 4He is 1.1 meV and 7.0 MeV respectively.Correct answer is '23.6'. Can you explain this answer?

Answer

Since number nucleo ns in

nucleus is 4, hence B.E. for

= 28.0 MeV, similarly B.E. for ²H nucleus (combination of one proton and one neutron) = 2.2 MeV.
Mass of

nucleus = 2 [Mess of proton] + 2 [Mass of neutron) - 28.0 MeV.
Mass of

nucleus = (Mass of proton) + [Mass of neutron) - 2.2 MeV.
In fusion reaction energy released, ΔE =

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