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A metallic rod completes its circuit as shown in the figure. The circuit is normal to a magnetic field of B = 0.15 tesla. If the resistances of the rod is 3Ω  the force required to move the rod with a constant velocity of 2 m/sec is - 
  • a)
     3.75 × 10–4 N
  • b)
    3.75 × 102 N 
  • c)
    3.75 × 10–2 N 
  • d)
    3.75 × 10–3 N 
Correct answer is option 'D'. Can you explain this answer?
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A metallic rod completes its circuit as shown in the figure. The circuit is normal to a magnetic field of B = 0.15 tesla. If the resistances of the rod is 3Ω the force required to move the rod with a constant velocity of 2 m/sec is -a)3.75 × 10–4Nb)3.75 × 102Nc)3.75 × 10–2Nd)3.75 × 10–3NCorrect answer is option 'D'. Can you explain this answer?
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A metallic rod completes its circuit as shown in the figure. The circuit is normal to a magnetic field of B = 0.15 tesla. If the resistances of the rod is 3Ω the force required to move the rod with a constant velocity of 2 m/sec is -a)3.75 × 10–4Nb)3.75 × 102Nc)3.75 × 10–2Nd)3.75 × 10–3NCorrect answer is option 'D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A metallic rod completes its circuit as shown in the figure. The circuit is normal to a magnetic field of B = 0.15 tesla. If the resistances of the rod is 3Ω the force required to move the rod with a constant velocity of 2 m/sec is -a)3.75 × 10–4Nb)3.75 × 102Nc)3.75 × 10–2Nd)3.75 × 10–3NCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metallic rod completes its circuit as shown in the figure. The circuit is normal to a magnetic field of B = 0.15 tesla. If the resistances of the rod is 3Ω the force required to move the rod with a constant velocity of 2 m/sec is -a)3.75 × 10–4Nb)3.75 × 102Nc)3.75 × 10–2Nd)3.75 × 10–3NCorrect answer is option 'D'. Can you explain this answer?.
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