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 over the semicircle x2 + y2 = ax in the positive quadrant is equal to -
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
over the semicircle x2+ y2= ax in the positive quadrant is equal to -a...
Let P(r,θ) be any point on the circle x2+y2 = ax
∴ x = r cos θ, y = r sin θ
= r(cos2 θ + sin2 θ) = r
and the equation of the circle
r2(cos2 θ + sin2 θ) = ar cos θ
=> r = a cos θ
The correct answer is C.
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Most Upvoted Answer
over the semicircle x2+ y2= ax in the positive quadrant is equal to -a...
Let P(r,θ) be any point on the circle x2+y2 = ax
∴ x = r cos θ, y = r sin θ
= r(cos2 θ + sin2 θ) = r
and the equation of the circle
r2(cos2 θ + sin2 θ) = ar cos θ
=> r = a cos θ
The correct answer is C.
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Community Answer
over the semicircle x2+ y2= ax in the positive quadrant is equal to -a...
Let P(r,θ) be any point on the circle x2+y2 = ax
∴ x = r cos θ, y = r sin θ
= r(cos2 θ + sin2 θ) = r
and the equation of the circle
r2(cos2 θ + sin2 θ) = ar cos θ
=> r = a cos θ
The correct answer is C.
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over the semicircle x2+ y2= ax in the positive quadrant is equal to -a)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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