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If 250 g of Ni at 120° C is dropped into 200 g of water at 100C contained by a calorimeter of 20 cal/0C heat capacity, what will be the final temperature of the mixture? (Given CNi = .106k cal/0C)
  • a)
    t = 200C
  • b)
    t = 65°C
  • c)
    220C
  • d)
    60°C
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If 250 g of Ni at 120° C is dropped into 200 g of water at 100C co...
Heat lost by Ni = heat gained by water + Calorimeter 
We know heat capacity of Ni. CNi = 0.106 kcal/0

So. 0.250 (0.106) (1200 - t ) = 
3.18 - 0 .071 = 0.2201 - 2.20  
0.247t= 5.38
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Most Upvoted Answer
If 250 g of Ni at 120° C is dropped into 200 g of water at 100C co...
Heat lost by Ni = heat gained by water + Calorimeter 
We know heat capacity of Ni. CNi = 0.106 kcal/0

So. 0.250 (0.106) (1200 - t ) = 
3.18 - 0 .071 = 0.2201 - 2.20  
0.247t= 5.38
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If 250 g of Ni at 120° C is dropped into 200 g of water at 100C co...
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If 250 g of Ni at 120° C is dropped into 200 g of water at 100C contained by a calorimeter of 20 cal/0C heat capacity, what will be the final temperature of the mixture? (Given CNi = .106k cal/0C)a)t = 200Cb)t = 65°Cc)220Cd)60°CCorrect answer is option 'C'. Can you explain this answer?
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