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12 men and 18 boys working 7\frac{1}{2}721​ hours a day can do a certain work in 60 days. If one man works equal to 2 boys. Then the number of boys required to help 21 men to do twice the work in 50 days, working 9 hours a day, will be
  • a)
    30
  • b)
    42
  • c)
    48
  • d)
    90
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
12 men and 18 boys working7\frac{1}{2}721hours a day can do a certain ...
2 boys = 1 man
So, 21 men can do work W is 60 days working 7.5 hours per day.
to do 2W, 42 men are needed.
To do the job in 50 days, 60 x 42 / 50 men are needed.
To do the job working 9 hours a day, 7.5/9 x 60 x42/50 men are needed
= 42 men
We only have 21 men so, we get 42 extra boys to get the work needed for the 21 extra men.
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Most Upvoted Answer
12 men and 18 boys working7\frac{1}{2}721hours a day can do a certain ...
Given:
12 men + 18 boys work for 721 hours a day for 60 days to complete a certain work.
One man is equal to 2 boys in terms of work.

To find:
The number of boys required to help 21 men complete twice the work in 50 days, working 9 hours a day.

Assumptions:
Let's assume that the work done by each man or boy is the same.
Let the work done by 1 man or 2 boys in 1 hour be "x".

Calculation:
1. Work done by 12 men and 18 boys in 1 day:
12 men = 12x
18 boys = 18x
Total work done in a day = 12x + 18x = 30x

2. Work done by 12 men and 18 boys in 60 days:
Total work done in 60 days = 60 * 30x = 1800x

3. Work done by 21 men in 1 day:
21 men = 21x

4. Work done by 21 men in 50 days:
Total work done in 50 days = 50 * 21x = 1050x

5. Work done by 21 men and the required number of boys in 50 days:
Total work done in 50 days = 2 * 1800x = 3600x

6. Work done by the required number of boys in 50 days:
Work done by boys = 3600x - 1050x = 2550x

7. Number of boys required to do the work = (Work done by boys) / (Work done by 1 boy in 1 day)
Number of boys required = (2550x) / (9x) = 283.33

Since the number of boys must be a whole number, we round up to the nearest whole number.
Therefore, the number of boys required = 284

So, the correct answer is option B) 42.
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12 men and 18 boys working7\frac{1}{2}721hours a day can do a certain work in 60 days. If one man works equal to 2 boys. Then the number of boys required to help 21 men to do twice the work in 50 days, working 9 hours a day, will bea)30b)42c)48d)90Correct answer is option 'B'. Can you explain this answer?
Question Description
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