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A long solenoid carrying a current produce’s a magnetic field B along its axis. If the current is doubled acid the number of turns per cm  is halved, the new value of the magnetic field is :
  • a)
    B/2
  • b)
    2B
  • c)
    4B
  • d)
    B
Correct answer is option 'D'. Can you explain this answer?
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A long solenoid carrying a current produce’s a magnetic fieldBal...

The correct answer is: B
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A long solenoid carrying a current produce’s a magnetic fieldBal...

The correct answer is: B
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A long solenoid carrying a current produce’s a magnetic fieldBal...
S a magnetic field inside the solenoid. The magnetic field lines are parallel and uniform along the axis of the solenoid. The strength of the magnetic field inside the solenoid is given by:

B = μ₀ * n * I

where B is the magnetic field strength, μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current flowing through the solenoid.

The direction of the magnetic field inside the solenoid can be determined using the right-hand rule. If you curl the fingers of your right hand in the direction of the current flow, your thumb will point in the direction of the magnetic field inside the solenoid.

The magnetic field outside the solenoid is relatively weak and varies with distance from the solenoid. The field lines outside the solenoid form loops around the solenoid. The strength of the magnetic field outside the solenoid decreases rapidly with increasing distance from the solenoid.

Overall, a long solenoid carrying a current produces a strong and uniform magnetic field inside the solenoid and a relatively weak and variable magnetic field outside the solenoid.
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